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2 years ago

21r-7-r+5=-52 solve for r

2 answers:

4 0

উত্তর: আর = - 2.5 আর = -2} ধাপে ধাপে ব্যাখ্যা: 21 র - 7-আর + 5 = - 52 20r - 2 = - 52 20r - 2 + 2 = - 52 + 2 20r = - 50 20r + 20 = - 50 ÷ 20 আর = - 2.5

malfutka [58]2 years ago

3 0

Answer:

r = - 2.5

$r=-2\frac{1}{2}$

Step-by-step explanation:

21r - 7 - r + 5 = - 52

20r - 2 = - 52

20r - 2 + 2 = - 52 + 2

20r = - 50

20r ÷ 20 = - 50 ÷ 20

r = - 2.5

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2 years ago

What is the sum? StartFraction 3 y Over y squared + 7 y + 10 EndFraction + StartFraction 2 Over y + 2 EndFraction

katovenus [111]

Answer:

$\dfrac{5}{y+5}$

Step-by-step explanation:

Here, we have to find the sum of 2 fractions:

1st fraction: $\dfrac{3y}{y^{2}+7y+10}$

2nd fraction: $\dfrac{2}{y+2}$

Considering the denominator of 1st fraction:

$y^{2}+7y+10$

Using factorization method:

$7y$ can be written as $(2y + 5y)$ .

$\Rightarrow y^{2}+2y+5y+10$

Taking 5 common from $5y+10$ and y common from $y^{2}+2y$ : $\Rightarrow y(y+2)+5(y+2)$

Now taking $(y+2)$ common:

$\Rightarrow (y+5)(y+2)$

$\dfrac{3y}{y^{2}+7y+10}$ can be written as $\dfrac{3y}{(y+5)(y+2)}$

Now, calculating the sum:

$\dfrac{2y}{(y+5)(y+2)} + \dfrac{2}{y+2}$

Taking LCM and solving:

$\Rightarrow \dfrac{3y+2(y+5)}{(y+5)(y+2)}\\\Rightarrow \dfrac{5y+10}{(y+5)(y+2)}\\\Rightarrow \dfrac{5(y+2)}{(y+5)(y+2)}\\\Rightarrow \dfrac{5}{(y+5)}$