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Akimi4 [234]
3 years ago
8

Which of the following completes the proof?

Mathematics
2 answers:
mihalych1998 [28]3 years ago
4 0

Answer:

c

Step-by-step explanation:

masha68 [24]3 years ago
3 0

Answer:

ITS EITHER A or D

Step-by-step explanation:

my question for the test is

Given: Segment AC is perpendicular to segment BD

Prove: ΔACB ~ ΔECD

Reflect ΔECD over segment AC. This establishes that ________. Then, translate point E' to point A. This establishes that ________. Therefore, ΔACB ~ ΔECD by the AA similarity postulate.

∠ABC ≅ ∠E'D'C'; ∠E'D'C' ≅ ∠ABC

∠ACB ≅ ∠E'C'D'; ∠D'E'C' ≅ ∠BAC

∠ACB ≅ ∠E'C'D'; ∠E'D'C' ≅ ∠ABC

∠ABC ≅ ∠E'D'C'; ∠D'E'C' ≅ ∠BAC

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Step-by-step explanation:

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For consumers making purchases online, 60% have devices made by Apple, 85% own a smartphone, and 75% use Venmo. Also, out of the
kompoz [17]

Answer:

The probability that a customer selected at random has an Apple device or own a smartphone or both is 0.94

Step-by-step explanation:

The percentage of costumers that have a device made by Apple = 60%

The percentage of customers that own a smartphone = 85%

The percentage of customers that use Venmo = 80%

The percentage out of the smartphone users that use Venmo = 80%

The probability both independent events A and B occurring = P(A) × P(B)

The exclusive probability of A or B occurring P(A XOR B) = P(A) + P(B) - 2 × P(A ∩ B)

Therefore, the probability of A or B or both occurring is given as follows;

P(A or B or Both) = P(A) + P(B) - 2 × P(A ∩ B) + P(A) × P(B)

Where A represent the percentage of costumers that have a device made by Apple and let B represent the percentage of users that have a smartphone, we have;

P(A or B or Both) = 0.6 + 0.85 - 2×0.6×0.85 + 0.6 × 0.85 = 0.94

Therefore, the probability that a customer selected at random has an Apple device or own a smartphone (or both), P(A or B or Both) = 0.94

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HEY CAN ANYONE PLS ANSWER DIS MATH QUESTION!!!
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Answer: C

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
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