You are given a table in which each row represents the coordinates of points. For example, in the first line, we have x=-7 and y=5. Work through the four given equations, one at a time, subbing -7 for x and 5 for y; is the equation still true? If yes, then you have found the correct answer. B is the exception; I'd suggest you check out equations A, C and D first, before focusing on B.
Example: D: (5)-5 = 2((-7) + 7) leads to 0 = 0. Is that true? If so, D is likely the correct answer.
Substitute
, so that

Then the resulting ODE in
is separable, with

On the left, we can split into partial fractions:

Integrating both sides gives




Now solve for
:


Y = 20x + 7 for instance
then just substitute the values
Hii!

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3v+4w-1
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
We use the distributive property to "distribute" the minus sign.
.
<em>Simplify!</em>
<em />
. <em>Which is our final answer.</em>
<em></em>
<em>Hope that this helped! Best wishes.</em>
<em></em>

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