Answer:
Use the distance formula on both points AC and AB.
<em>Distance formula is this</em><em>:</em>
<em>\begin{gathered}d=\sqrt{(x2-x1)^2+(y2-y1)^2} \\\\d=\sqrt{(1--5)^2+(8--7)^2} \\\\d=\sqrt{(6)^2+(15)^2} \\\\d=\sqrt{36+225} \\\\d=\sqrt{261} \\\\\end{gathered}d=(x2−x1)2+(y2−y1)2d=(1−−5)2+(8−−7)2d=(6)2+(15)2d=36+225d=261</em>
Distance for AC is 16.16
Now do the same with the numbers for AB and get the distance of 5.39
2. To get the area, use the formula 1/2 x base x height
AB is the base and AC is the height.
1/2 x 16.16 x 5.39 = 43.55
the answer is 43.5
Answer:
<h2>The range: {-6, -10, -14, -18}</h2>
Step-by-step explanation:
Put the values of x from the domain to the equation of a function y = 4x - 2:
for x = -1
y = 4(-1) - 2 = -4 - 2 = -6
for x = -2
y = 4(-2) - 2 = -8 - 2 = -10
for x = -3
y = 4(-3) - 2 = -12 - 2 = -14
for x = -4
y = 4(-4) - 2 = -16 - 2 = -18
Answer:
The minimum number of words left to write is 215
Step-by-step explanation:
Let
w -----> the number of words left to write
we know that
The number of words left to write plus the words written so far must be greater than or equal to 500 words
Remember that the word "at least" means "greater than or equal to"

Solve for w
Subtract 285 both sides

The minimum number of words left to write is 215