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fenix001 [56]
3 years ago
9

Combustión: Cada vez que enciendes la estufa lo que ocurre es la combustión de un hidrocarburo. Combustión en palabras simples q

uemar, en este caso el hidrocarburo del gas con el oxígeno del aire. La reacción química se muestra abajo. ¿Cuántos gramos de dióxido de carbono (CO2) se producen si se quema 40 gramos del hidrocarburo ( C3H8 )?
Biology
1 answer:
docker41 [41]3 years ago
4 0

Answer:

120 gramos de CO₂

Explanation:

La ecuación química balanceada para la combustión del hidrocarburo propano (C₃H₈) es la siguiente:

C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O

Por lo tanto, 1 mol de C₃H₈ produce 3 moles de CO₂. Para convertir las moles a gramos usamos el peso molecular (PM) de cada compuesto:

PM(C₃H₈)= (3 x 12 g/mol C) + (8 x 1 g/mol H) = 44 g/mol

masa de C₃H₈ = 1 mol x 44 g/mol = 44 g

PM(CO₂) = (1 x 12 g/mol C) + (2 x 16 g/mol O) = 44 g/mol

masa de CO₂ = 3 mol x 44 g/mol = 132 g

Ahora podemos ver que se producen 132 gramos de CO₂ (3 moles) a partir de 44 gramos de C₃H₈ (1 mol) ⇒ 132 CO₂/ 44 g C₃H₈

Multiplicamos la relación estequiométrica por la cantidad de propano que tenemos para calcular la cantidad de CO₂ producida:

40 g C₃H₈ x 132 CO₂/ 44 g C₃H₈ = 120 g CO₂

Entonces, se producen 120 gramos de dióxido de carbono al quemar 40 gramos de hidrocarburo C₃H₈.

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