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Hoochie [10]
3 years ago
14

Write the equation of the line that passes through (−3, 5) and (2, 10) in slope-intercept form.

Mathematics
1 answer:
Paladinen [302]3 years ago
7 0

Answer:

gradient =y2-y1÷x2-x1

=10-5÷2-(-3)

1

y-y1=m(x-x1)

y-5=1(x-(-3))

y=x+2

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N- 26 = -13 i need to solve for n
emmainna [20.7K]

Answer:

The answer I beliebe is n=13.

Hope this helps you.

3 0
4 years ago
Read 2 more answers
If 3/5 of the certain length is 210m then 5/7 of length is​
Mamont248 [21]

Answer:

250 m

Step-by-step explanation:

Let the total length be x m.

\therefore \:  \frac{3}{5}  \times x = 210 \\ x = 210 \times  \frac{5}{3}  \\ x = 70 \times 5 \\ x = 350 \: m \\  \\  \frac{5}{7}  \times x =  \frac{5}{7}  \times 350 = 5 \times 50 = 250 \: m

4 0
3 years ago
Read 2 more answers
A rectangle has a length of 10 cm and a width of 7 cm. What is its perimeter?
spin [16.1K]

Answer:

34 cm

Step-by-step explanation:

Keep in mind that the perimeter of a rectangle is the sum of the measures of its sides. This means that the sum of the longer sides and the shorter sides is the perimeter of the rectangle.

Let "L" represent the longer side (length) of the rectangle and "S" represent the shorter side (width) of the rectangle.

⇒ Perimeter of rectangle = L + S + L + S

⇒ Perimeter of rectangle = 2(L) + 2(S)

⇒ Perimeter of rectangle = 2(L + S)

Now, let's substitute the length and the width in the perimeter and simplify.

⇒ Perimeter of rectangle = 2(10 + 7)                                                [L = 10; S = 7]

⇒ Perimeter of rectangle = 2(17)

⇒ Perimeter of rectangle = 34 cm

5 0
2 years ago
The US Postal rates for a first class letter are
Gnom [1K]

Answer:

.46

Step-by-step explanation:

.46 for up to one ounce

7 0
3 years ago
You are contacted by a phone-in technical support business that is interested in some information about the amount of time their
Gennadij [26K]

Answer:

The average hold time is 10.47 minutes.

Step-by-step explanation:

Let <em>X</em> = time the customers of a phone-in technical support business spend on hold.

The population mean of the random variable <em>X</em> is, <em>μ</em> = 11 minutes.

The population standard deviation of the random variable <em>X</em> is, <em>σ </em>= 1.16 minutes.

A random sample size, <em>n</em> = 62 callers are selected.

According to the Central limit theorem if large samples (<em>n</em> > 30) are selected from an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> then the sampling distribution of sample mean (\bar x) follows a Normal distribution.

The mean of the sampling distribution of sample mean is:

\mu_{\bar x}=\mu=11

The standard deviation of the sampling distribution of sample mean is:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{1.16}{\sqrt{62}}=0.147

It is provided that P(\bar X>a)=0.79.

Compute the value of <em>a</em> as follows:

P(\bar X>a)=0.79\\P(Z>z)=0.79\\1-P(Z

The value of <em>z</em> for the above probability is, <em>z</em> = -0.806.

The value of <em>a</em> is:

z=\frac{a-\mu_{\bar x}}{\sigma_{\bar x}}\\-0.806=\frac{a-11}{0.147}\\a=11-(0.86\times 0.147)\\a=10.87

Thus, the average hold time is 10.47 minutes.

3 0
3 years ago
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