Ask question

Ask question

All categories

ivanzaharov [21]

2 years ago

11

at a museum, a model of a rocket is 3 feet high. the model has a scale of 1 foot to 121 feet. the museum manager will create a n

ew model of the rocket with a scale of 1 foot to 33 feet. what will be the height, in feet, of the new model of the rocket?

2 answers:

Alexandra [31]2 years ago

5 0

Your answer is 30 feet

notka56 [123]2 years ago

3 0

Answer:

0.79 ft ≈ For 30 feet

Step-by-step explanation:

This is even a tricky question for me, I am pretty sure this would be around 0.79 feet. But I am not too sure so I am very sorry if I am incorrect.

I hope this helps, if it doesn't then just message me and ill be more than happy to help :)

You might be interested in

A + B= 1233445667788

Archy [21]

Should be no lmk if it’s not

8 0

3 years ago

Read 2 more answers

4x – 9 = 2x + 15 can someone explain the system used to answer this question

PSYCHO15rus [73]

The system is comprised of two processes
that go on at the same time:

   #1). Do what ever you want to, to get 'x'
   on one side of the equation, and
   everything else on the other side.
   #2). Whatever you do to one side of the equation,
   you must immediately do the same thing to the
   other side.

That's the system.

Here's how it works: (I can't believe you're in high school math
and you've never seen, studied, or practiced this before.)

You said that       4x - 9 = 2x + 15
and you need to find
what 'x' is.

Subtract 2x from each side: 2x - 9 =   15

Add 9 to each side:        2x =      24

Divide each side by 2 : x =   12 .

4 0

3 years ago

Meredith picked 4 times as many green peppers as red peppers. If she picked a total of 20 peppers, how many green peppers did sh

Misha Larkins [42]

Let's have X represent the number of red peppers Meredith picked:

X = red peppers

We know that Meredith picked 4 times as many green peppers as red peppers, so based on this:

green peppers = 4*(red peppers) = 4X

In total, she picked 20, so:

Red peppers + Green peppers = 20
X + 4X = 20
5X = 20
X = 4

So, Meredith picked 4 red peppers and 16 (4 times 4) green peppers!

4 0

3 years ago

45% como una fraction en forma reducida

Butoxors [25]

45/100 ..............................

7 0

3 years ago

Read 2 more answers

All 3 questions 3 pictures for find the missing angles, please with reasoning why? 100 points

Katyanochek1 [597]

Answer:

Problem 1)

$m\angle DEG = 38^\circ$

Problem 2)

$m\angle x =140^\circ \text{ and } m\angle y = 49^\circ$

Problem 3)

$m\angle EDG = 65^\circ$

Step-by-step explanation:

Problem 1: ∠DEG

From the diagram, we know that ∠DFG intercepts Arc DG.

Inscribed angles have half the measure of its intercepted arc. Therefore:

$\displaystyle \frac{1}{2}m\stackrel{\frown}{DG}=m\angle DFG$

We know that m∠DFG = 38°. So:

$\displaystyle \frac{1}{2}m\stackrel{\frown}{DG}=38\Rightarrow m\stackrel{\frown}{DG}=76^\circ$

∠DEG also intercepts Arc DG. Hence:

$\displaystyle m\angle DEG=\frac{1}{2}m\stackrel{\frown}{DG}$

We know that Arc DG measures 76°. Hence:

$\displaystyle m\angle DEG =\frac{1}{2}\left(76\right)=38^\circ$

Alternate Explanation:

Since ∠DEG and ∠DFG intercept the same arc, ∠DEG ≅ DFG. So, m∠DEG = m∠DFG = 38°.

Problem 2: Circle with Centre O

(Let the bottom left corner be A, upper be B, and right be C.)

∠ACB intercepts Arc AC.

Inscribed angles have half the measure of its intercepted arc. Therefore:

$\displaystyle \frac{1}{2}m\stackrel{\frown}{AC}=m \angle ACB$

Since m∠ACB = 70°:

$\displaystyle \frac{1}{2}m\stackrel{\frown}{AC}=70\Rightarrow m\stackrel{\frown}{AC}=140^\circ$

∠<em>x</em> is a central angle and also intercepts Arc AC.

The measure of a central angle is equal to its intercepted arc. Thus:

$\displaystyle m\angle x =m\stackrel{\frown}{AC}=140^\circ$

The sum of the interior angles of a polygon is given by the formula:

$(n-2)\cdot 180^\circ$

Where <em>n</em> is the number of sides.

Since the inscribed figure is a four-sided polygon, its interior angles must total:

$(4-2)\cdot 180^\circ =360^\circ$

Therefore:

$21+70+y+(360-x)=360$

Substitute and solve for <em>y:</em>

$91+y+(360-140)=360\Rightarrow y +311=360\Rightarrow m\angle y = 49^\circ$

Problem 3: ∠EDG

∠EFG intercepts Arc EDG.

Inscribed angles have half the measure of its intercepted arc. Therefore:

$\displaystyle \frac{1}{2}m\stackrel{\frown}{EDG}=m\angle EFG$

Since m∠EFG = 115°:

$\displaystyle \frac{1}{2}m\stackrel{\frown}{EDG} = 115\Rightarrow m\stackrel{\frown}{EDG} = 230^\circ$

A full circle measures 360°. Hence:

$m\stackrel{\frown}{EDG}+m\stackrel{\frown}{EFG}=360^\circ$

Since we know that Arc EDG measures 230°:

$230^\circ + m\stackrel{\frown}{EFG}=360$

Solve for Arc EFG:

$m\stackrel{\frown}{EFG}=130^\circ$

∠EDG intercepts Arc EFG.

Inscribed angles have half the measure of its intercepted arc. Therefore:

$\displaystyle m\angle EDG = \frac{1}{2}m\stackrel{\frown}{EFG}$

Since we know that Arc EFG measures 130°:

$\displaystyle m\angle EDG = \frac{1}{2}(130)=65^\circ$

7 0

3 years ago

Read 2 more answers