Question

Hey, Can someone help me solve 2x²=63-5x using the quadratic formula. ( In algebra 1 by the way)

Answer 1

I don’t want to sound d u m b but use photomath it really helped me with quadratic formula it shows steps too.

Answer 2

Answer (if we're solving for x):

$x=-7$ or $\frac{9}{2}$

Step-by-step explanation:

1. Rearrange the terms from $2x^{2} =63-5x$ to $2x^{2}=-5x+63$
2. Move the terms to the left side: $2x^{2}-(-5x+63)=0$
3. Use the "sum-product" pattern: $2x^2+14x-9x-63=0$
4. Get the common factor drom the 2 pairs:$2x(x+7)-9(x+7)=0$
5. Rewrite the equation in factored form as $(2x-9)(x+7)=0$
6. Create 2 equations from $(2x-9)(x+7)=0$: $2x-9=0\\x+7=0$
7. This means that $x$ can either be $-7 (-7+7=0=x+7)$ or $\frac{9}{2} (\frac{8}{2}=4; \frac{9}{2}=4.5)$