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beks73 [17]
3 years ago
11

Can you guys help me?

Mathematics
1 answer:
denis-greek [22]3 years ago
6 0
Pretty sure you have to use the Pythagorean Theorem.
a^2+b^2=c^2

So you would plug in your numbers that you already have (6 and 10) But notice that 10 is the hypotenuse (longest side) so
6^2+x=10^2

Then you would solve it and you should end up with 11.6619
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Step-by-step explanation:

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on a certain hot Summer's Day 613 people use the public swimming pool the daily prices are $1.75 for children $2.25 for adults t
Elodia [21]

389 children and 224 adults were at the pool that day.

Step-by-step explanation:

Cost of one child ticket = $1.75

Cost of one adult ticket = $2.25

Total people = 613

Total receipts worth = $1184.75

Let,

Number of children = x

Number of adults = y

According to given statement;

x+y=613    Eqn 1

1.75x+2.25y=1184.75    Eqn 2

Multiplying Eqn 1 by 1.75

1.75(x+y=613)\\1.75x+1.75y=1072.75\ \ \ Eqn\ 3

Subtracting Eqn 3 from Eqn 2

(1.75x+2.25y)-(1.75x+1.75y)=1184.75-1072.75\\1.75x+2.25y-1.75x-1.75y=112.00\\0.50y=112.00

Dividing both sides by 0.50

\frac{0.50y}{0.50}=\frac{112.00}{0.50}\\y=224

Putting y=224 in Eqn 1

x+224=613\\x=613-224\\x=389\\

389 children and 224 adults were at the pool that day.

Keywords: linear equation, subtraction

Learn more about linear equations at:

  • brainly.com/question/11236033
  • brainly.com/question/11306893

#LearnwithBrainly

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Step-by-step explanation:

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3 years ago
70 coins of 10 paise and 50 paise are kept in a purse. if the total value of the money in the purse is Rs 19 . find the no. of e
Allushta [10]

Answer:

10=40

50=30

Step-by-step explanation:

Suppose the number of 10 paise coins =x

∴ the number of 50 paise coins =70−x

Now, value of 10 paise coins = Rs.  

10 x  and value of 50 paise coins = Rs.   2 70−x

Total value of coins =   10 x +  2 70−x

​∴  10 x  +  2 70−x  =19

Multiplying both sides by 10, (LCM of 10,2=10), we get  

x+5(70−x)=19×10    

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​∴x=40

∴ number of 10 paise coins =40  

Number of 50 paise coins =70−40=30.

7 0
3 years ago
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