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Serhud [2]
3 years ago
5

Rania is playing with her friend Arun, and they are setting dominoes across the room. Each domino is 2 inches long. They have al

ready placed 10 dominoes in a row. The room is 10 feet long and they want to know how many more dominoes they can set up before they reach all the way across the room. Does the inequality 2d + 20 < 120 model this situation? Explain why or why not.​
Mathematics
1 answer:
8_murik_8 [283]3 years ago
5 0

May you please take a Pic of the question

Step-by-step explanation:

Thank you

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5.6 - 0.105 = 5.505 What's The answer
adelina 88 [10]
<span>5.505 thats the answer it says equals</span>
6 0
4 years ago
What is the formula for the expected number of successes in a binomial experiment with n trials and probability of success​ p? C
charle [14.2K]

Answer:

(D)E[ X ] =np.

Step-by-step explanation:

Given a binomial experiment with n trials and probability of success​ p,

f(x)=\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}, 0\leq  x\leq n

E(X)=\sum_{x=0}^{n}xf(x)= \sum_{x=0}^{n}x\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}

Since each term of the summation is multiplied by x, the value of the term corresponding to x = 0 will be 0. Therefore the expected value becomes:

E(X)=\sum_{x=1}^{n}x\left(\begin{array}{c}n\\x\end{array}\right)p^x(1-p)^{n-x}

Now,

x\left(\begin{array}{c}n\\x\end{array}\right)= \frac{xn!}{x!(n-x)!}=\frac{n!}{(x-)!(n-x)!}=\frac{n(n-1)!}{(x-1)!((n-1)-(x-1))!}=n\left(\begin{array}{c}n-1\\x-1\end{array}\right)

Substituting,

E(X)=\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^x(1-p)^{n-x}

Factoring out the n and one p from the above expression:

E(X)=np\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^{x-1}(1-p)^{(n-1)-(x-1)}

Representing k=x-1 in the above gives us:

E(X)=np\sum_{k=0}^{n}n\left(\begin{array}{c}n-1\\k\end{array}\right)p^{k}(1-p)^{(n-1)-k}

This can then be written by the Binomial Formula as:

E[ X ] = (np) (p +(1 - p))^{n -1 }= np.

5 0
3 years ago
Angie and Kenny play online video games. Angie buys 1 software package and 3 months of game play. Kenny buys 1 software package
andrey2020 [161]

Answer:The cost of one month of game-play =$20


Step-by-step explanation:

Let the cost of one month of gameplay be x

Then cost of game-play bought by Angie =3x.....(1)

and Then cost of game-play bought by Kenny=4x......(2)

Cost of each software package =$50......(3)

The the total cost =240= sum of costs of software bought by both of them and game-play)=50+50+3x+4x

⇒240=100+7x.......→(by adding like terms)

⇒140=7x⇒x=20.....→( dividing both sides by 7 )

∴the cost of one month of game-play =$20



8 0
3 years ago
Read 2 more answers
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jek_recluse [69]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
Help please I’m so dumb for this
Keith_Richards [23]

Answer:

you are dumbbbbbb

Step-by-step explanation:

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3 0
4 years ago
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