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Serhud [2]
3 years ago
5

Rania is playing with her friend Arun, and they are setting dominoes across the room. Each domino is 2 inches long. They have al

ready placed 10 dominoes in a row. The room is 10 feet long and they want to know how many more dominoes they can set up before they reach all the way across the room. Does the inequality 2d + 20 < 120 model this situation? Explain why or why not.​
Mathematics
1 answer:
8_murik_8 [283]3 years ago
5 0

May you please take a Pic of the question

Step-by-step explanation:

Thank you

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Describe the transformation from the graph of f(x) = x + 2 to the graph of g(x) = x − 7.
galina1969 [7]
The graph went down 9
7 0
3 years ago
HELP ASAP:
tekilochka [14]

Answer:

Here's how I would do it.  

Step-by-step explanation:

If two triangles are similar, corresponding sides are in the same ratio.

We know the measures of b and a, so we can calculate the ratio b/a.

d and b are in the same ratio, so

\begin{array}{rcl}\dfrac{d}{c}& = & \dfrac{b}{a}\\d & = & c \times \dfrac{b}{a}\\\end{array}

We know the measures of c, b, and a, so we can calculate the value of d.

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3 years ago
Find dy/dx if y =x^3+5x+2/x²-1
stiks02 [169]

<u>Differentiate using the Quotient Rule</u> –

\qquad\pink{\twoheadrightarrow \sf \dfrac{d}{dx} \bigg[\dfrac{f(x)}{g(x)} \bigg]= \dfrac{ g(x)\:\dfrac{d}{dx}\bigg[f(x)\bigg] -f(x)\dfrac{d}{dx}\:\bigg[g(x)\bigg]}{g(x)^2}}\\

According to the given question, we have –

  • f(x) = x^3+5x+2
  • g(x) = x^2-1

Let's solve it!

\qquad\green{\twoheadrightarrow \bf \dfrac{d}{dx}\bigg[ \dfrac{x^3+5x+2 }{x^2-1}\bigg]} \\

\qquad\twoheadrightarrow \sf \dfrac{(x^2-1) \dfrac{d}{dx}(x^3+5x+2) - ( x^3+5x+2)  \dfrac{d}{dx}(x^2-1)}{(x^2-1)^2 }\\

\qquad\twoheadrightarrow \sf \dfrac{(x^2-1)(3x^2+5)  -  ( x^3+5x+2) 2x}{(x^2-1)^2 }\\

\qquad\pink{\sf \because \dfrac{d}{dx} x^n = nx^{n-1} }\\

\qquad\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-(2x^4+10x^2+4x)}{(x^2-1)^2 }\\

\qquad\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-2x^4-10x^2-4x}{(x^2-1)^2 }\\

\qquad\green{\twoheadrightarrow \bf \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}\\

\qquad\pink{\therefore  \bf{\green{\underline{\underline{\dfrac{d}{dx} \dfrac{x^3+5x+2 }{x^2-1}}  =  \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}}}}\\\\

7 0
2 years ago
Are 4 7/9 and repeating 4.7 are they equal?
cluponka [151]

Answer:

Step-by-step explanation:

These two expressions are definitely not equal.

4 7/9 is a repeating decimal:  4.77777 ...    (use your calculator)

whereqs 4.7 is NOT a repeating decimal.

4 0
3 years ago
3y^4+9y^3-120y^2=0 Need Answer ASAP
Shkiper50 [21]

Answer:

y  =  0 ,  5 ,  − 8

(* ̄3 ̄)╭

7 0
3 years ago
Read 2 more answers
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