Question

(3x 2 + 2x - 3)(x - 1) solve

Answer 1

Answer:

$x=\frac{-1(+)\sqrt{10}} {3}$

$x=\frac{-1(-)\sqrt{10}} {3}$

$x=1$

Step-by-step explanation:

we have

$(3x^{2}+2x-3)(x-1)$

Solve the quadratic equation

$(3x^{2}+2x-3)$

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$3x^{2}+2x-3=0$  

so

$a=3\\b=2\\c=-3$

substitute in the formula

$x=\frac{-2(+/-)\sqrt{2^{2}-4(3)(-3)}} {2(3)}$

$x=\frac{-2(+/-)\sqrt{40}} {6}$

$x=\frac{-2(+/-)2\sqrt{10}} {6}$

$x=\frac{-2(+)2\sqrt{10}} {6}=\frac{-1(+)\sqrt{10}} {3}$

$x=\frac{-2(-)2\sqrt{10}} {6}=\frac{-1(-)\sqrt{10}} {3}$

therefore

The solutions of the equation

$(3x^{2}+2x-3)(x-1)$

are

$x=\frac{-1(+)\sqrt{10}} {3}$

$x=\frac{-1(-)\sqrt{10}} {3}$

$x=1$