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3 years ago

Is anyone good at geometry if so can you help me please ?

Mathematics

1 answer:

ololo11 [35]3 years ago

3 0

Answer:

a. ∆BAC & ∆DEC

b. they have a vertical angle because they both share c, and <a = <e. If two angles are congruent, the third must be congruent as well.

c. √90 = 3√10

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Please help with 10!

bixtya [17]

Answer:

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Step-by-step explanation:

4 0

3 years ago

1 - 3x = 3x + 1 solve for x

lakkis [162]

Answer: x = 0

Step-by-step explanation:

1 - 3x = 3x + 1

then add 3x on both sides

1 = 6x + 1

then subtract 1 on both sides

0 = 6x

then divide by 6 on both sides

0 = x

so x = 0

3 0

3 years ago

Read 2 more answers

PLS HELP ILL GIVE BRAINLIEST

cluponka [151]

So you start of by finding the median. The median in this case would be 43. Then you find the median of both the lower (36) and the upper (53) half of the data. Then the find the difference between those two number. So you would do 53-36 which would make the answer 17

8 0

4 years ago

Using the inequity -16k-32>-48

3241004551 [841]

Answer:

k<1

Step-by-step explanation:

1. Add 32 to both sides

-16k-32+32>-48+32

2. Simplify

-16k>-16

3. Reverse the sign (You only reverse the sign if you are DIVIDING BY a negative.)

-16k/-16 = k

-16/-16 = 1

You're left with k < 1

Your number line graph should be an open circle at 1 going to the left.

8 0

4 years ago

Find y as a function of x if y"' + 9y' = 0, y(0) = 6, y'(0) = 9, y"(0) = 18. y(x) =

Andreas93 [3]

Answer:

y(x) = 8 - 2cos 3x + 3sin 3x

Step-by-step explanation:

Given the equation:

y''' + 9y' = 0

The characteristic equation :

⇒r³ + 9r =0

Solving for r, we get r = 0 and r = ± 3i

The general equation for such equation is :

y = C₁ + C₂cos 3x + C₃sin 3x

Given:

y(0) = 6

Thus, Applying in the above equation, we get

6 = C₁ + C₂ .......................................................1

Differentiating y , we get:

y' = -3C₂sin 3x + 3C₃cos 3x

Given:

y'(0) = 9

Thus, Applying in the above equation, we get

9 = 3C₃

or,

C₃ = 3

Differentiating y' , we get:

y'' = -9C₂cos 3x - 9C₃sin 3x

Given:

y''(0) = 18

Thus, Applying in the above equation, we get

18 = -9C₂

or,

C₂ = -2

Applying in equation 1 , we get:

C₁ = 8

Thus,

y(x) = 8 - 2cos 3x + 3sin 3x

4 0

4 years ago