Plzzzzzz help me swear will mark u brainiest
1 answer:
You might be interested in
Answer:
a) see attached, a = g sin θ
b)
c) v = √(2gL (1-cos θ))
Explanation:
In the attached we can see the forces on the sphere, which are the attention of the bar that is perpendicular to the movement and the weight of the sphere that is vertical at all times. To solve this problem, a reference system is created with one axis parallel to the bar and the other perpendicular to the rod, the weight of decomposing in this reference system and the linear acceleration is given by
Wₓ = m a
W sin θ = m a
a = g sin θ
b) The diagram is the same, the only thing that changes is the angle that is less
θ' = 9/2 θ
c) At this point the weight and the force of the bar are in the same line of action, so that at linear acceleration it is zero, even when the pendulum has velocity v, so it follows its path.
The easiest way to find linear speed is to use conservation of energy
Highest point
Em₀ = mg h = mg L (1-cos tea)
Lowest point
Emf = K = ½ m v²
Em₀ = Emf
g L (1-cos θ) = v² / 2
v = √(2gL (1-cos θ))
Answer:
Maximum height reached by the rocket is
total time of the motion of rocket is given as
Explanation:
Initial speed of the rocket is given as
acceleration of the rocket is given as
engine stops at height h = 150 m
so the final speed of the rocket at this height is given as
so maximum height reached by the rocket is given as the height where its final speed becomes zero
so we will have
Now the total time of the motion of rocket is given as
1) time to reach the height of 150 m
2) time to reach ground from this height
so total time of the motion of rocket is given as