4 years ago

Find out the kinetic energy of a body of mass 2kg moving with the speed of 3m/s

1 answer:

7 0

Kinetic energy = 1/2mv2

= 1/2 x 2 x 3^2
= 9J

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Usimov [2.4K]

A.(20*40)/64=12.5 hope i helped

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Scilla [17]

Answer:

The magnitude of the average angular acceleration of the disk is $4139.74\ rad/s^2$ .

Explanation:

Given that,

Angular velocity, $\omega_i=968.7\ rad/s$

The disk comes to rest, $\omega_i=0$

Time, t = 0.234 s

We need to find the magnitude of the average angular acceleration of the disk. It is given by change in angular velocity per unit time. So,

$\alpha =\dfrac{\omega f}{t}\\\\\alpha =\dfrac{968.7\ rad/s}{0.234\ s}\\\\\alpha =4139.74\ rad/s^2$

So, the magnitude of the average angular acceleration of the disk is $4139.74\ rad/s^2$ .

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Karo-lina-s [1.5K]

They flow i guess but dont quote me on that

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inn [45]

i think its a, good luck on your test

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