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Rudik [331]
3 years ago
10

Find out the kinetic energy of a body of mass 2kg moving with the speed of 3m/s

Physics
1 answer:
Varvara68 [4.7K]3 years ago
7 0
Kinetic energy = 1/2mv2

= 1/2 x 2 x 3^2
= 9J
You might be interested in
Lora (of mass 47.4 kg) is an expert skier. She
Harrizon [31]

Answer:

Kinetic energy is 242.7 Joule

Explanation:

m = 47.4 kg

v = 3.2m/s²

Now,

K.E. = 1/2 × m × v²

or, K.E. = 1/2 × 47.4 × 3.2²

or, K.E. = 242.7 Joule

6 0
2 years ago
Science fiction movies that include explosion sound effects for battles in space are not scientifically correct. Why is this?
Reil [10]

B. There is not enough matter in space to transmit sound waves.

Explanation:

Sound waves are created when there is a vibration of the particles in a medium. For example, our voice is an example of sound wave: when we speak, the molecules of air around us start vibrating, producing regions of higher concentration of molecules (called compressions) and of lower concentration (called rarefactions). It is clear from this definition that sound waves can only propagate if there is a physical medium: such as a gas, a liquid or a solid, but sound waves cannot propagate through empty space.

Since space is almost empty, the correct choice is

B. There is not enough matter in space to transmit sound waves.

6 0
3 years ago
The 60.0 kg skier shown below is skiing down a 35.0 degree incline where the magnitude of the friction force is 38.5N
Sunny_sXe [5.5K]

Answer:

a) 4.98m/s²

b) 481.66N

Explanation:

a) Using the Newtons second law of motion

\sum F_x = ma_x\\F_m - F_f = ma_x\\Wsin \theta - F_f = ma_x\\mgsin \theta - F_f = ma_x\\

m is the mass of the object

g is the acceleration due to gravity

Fm is the moving force acting along the plane

Ff is the frictional force opposing the moving froce

a is the acceleration of the skier

Given

m = 60kg

g = 9.8m/s²

\theta = 35°

Ff = 38.5N

Required

acceleration of the skier a

Substituting into the formula;

60(9.8)sin 35^0 - 38.5 = 60a\\588sin35^0 - 38.5 = 60a\\337.26 - 38.5 = 60a\\298.76 = 60a\\a = 298.76/60\\a = 4.98m/s^2\\

Hence the acceleration of the skier is 4.98m/s²

b) The normal force on the skier is expressed as;

N = Wcosθ

N = mgcosθ

N = 60(9.8)cos 35°

N = 588cos 35°

N = 481.66N

Hence the normal force on the skier is 481.66N

5 0
3 years ago
Stop lamps must be visible within____ to the rear
Charra [1.4K]
The answer is 300 feet. The stop lamp or lamps on the rear of a vehicle must show a red light that is set in motion upon application of the service or foot brake and, in a vehicle manufactured or assembled on or after January 1, 1964, must be visible from a distance of not less than 300 feet to the rear in normal sunlight. Take note, if the vehicle is manufactured or assembled January 1, 1964, the stop lamp or lamps must be visible from a distance of not less than 100 feet. Also, the stop lamp may be combined with one or more other rear lamps. 
3 0
3 years ago
Read 2 more answers
HELP!!
tresset_1 [31]

Answer:

So do 2400 divided by 70. I got 34.285714 and the numbers behind the decimal are repeating. If you round it you get 34.3

3 0
2 years ago
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