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Rufina [12.5K]
3 years ago
15

Use the worked example above to help you solve this problem. A car traveling at a constant speed of 27.9 m/s passes a trooper hi

dden behind a billboard, as in the figure. One second after the speeding car passes the billboard, the trooper sets off in chase with a constant acceleration of 3.36 m/s2.
(a) How long does it take the trooper to overtake the speeding car?
Physics
1 answer:
Sidana [21]3 years ago
7 0
H h h huh h jvjvhvuvuvuvyv
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Wow free poin ts !!!!
zubka84 [21]
Thank you very much, very much appreciated.
8 0
3 years ago
Read 2 more answers
Find the magnitude of vector A = i - 2j + 3k O V14 10 O4
koban [17]

Answer:

The magnitude of the given vector is \sqrt{14}

Explanation:

For any given vector \overrightarrow{r}=x\widehat{i}+y\widehat{j}+z\widehat{k}

The magnitude is given by

|r|=\sqrt{x^2+y^2+z^2}

comparing with the given vector \overrightarrow{A}=1\widehat{i}-2\widehat{j}+3\widehat{k}

we get

x = 1, y = -2, z = 3

Thus the magnitude of vector A is

|r|=\sqrt{1^2+(-2)^2+3^2}\\\\\therefore |r|=\sqrt{14}

7 0
3 years ago
A boat travels with a velocity equal to 14.0 meters per second, east in 6.15 seconds. What distance in meters does the boat trav
Y_Kistochka [10]

Answer:

Distance, d is 86.1 meters.

Explanation:

Given the following data;

Time, t = 6.15secs

Velocity = 14m/s

Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.

Mathematically, velocity is given by the equation;

Velocity = \frac{distance}{time}

V = \frac{d}{t}

d = Vt

Substituting into the above equation;

d = 14 * 6.15

d = 86.1m

Hence, the distance traveled by the boat is 86.1 meters.

6 0
3 years ago
A very loud train whistle has an acoustic power output of 100 W. If the sound energy spreads out spherically, what is the intens
valentina_108 [34]

Answer

given,

Power output of loud train = 100 W

Distance of intensity level from train= 100 m

I₀ = 10⁻¹² W/m²                      

Intensity of sound = ?        

we know,                            

I = \dfrac{P}{Area}          

I = \dfrac{P}{4\pi r^2}          

I = \dfrac{100}{4\pi 100^2}          

I =7.957\times 10^{-4}\ W/m^2

Intensity level                              

  = 10 log(\dfrac{I}{I_0})

  = 10 log(\dfrac{7.975\times 10^{-4}}{10^{-12}})

  = 10 \times 8.900

  = 89 dB

7 0
4 years ago
Witch SI units are commonly used to measure mass and weight
Minchanka [31]

Explanation: Mass is Kilogram

Weight is Newton

8 0
3 years ago
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