Answer:
Yes, his collection will be complete by the time his grandfather visits
Step-by-step explanation:
Here, we want to know if his collection would be complete by the time his grandfather visits.
From the question;
he has collected 13 different quarters in 2.25 months
At the same rate, x different quarters will be collected in 9 months
Thus, mathematically;
x * 2.25 = 13 * 9
x = (13 * 9)/2.25 = 52
Thus, at this rate he would have collected 52 quarters in 9 months.
Since he has only 50 to collect, it means his collection would be complete by the time his grandfather visits
(2x^2+6x-11)-(5x^2-x+7)
Pretend that there is a -1 in front of the second bracket
-1(5x^2-x+7)=-5x^2+x-7
2x^2+6x-11-5x^2+x-7
2x^2-5x^2+6x+x-11-7 ( combine like terms)\
-3x^2+7x-18
Answer: d. -3x^2+7x-18
Answer:
x= -2 OR x=10
Step-by-step explanation:
(x−3)(x−5)=35
Step 1: Simplify both sides of the equation.
x2−8x+15=35
Step 2: Subtract 35 from both sides.
x2−8x+15−35=35−35
x2−8x−20=0
Step 3: Factor left side of equation.
(x+2)(x−10)=0
Step 4: Set factors equal to 0.
x+2=0 or x−10=0
x=−2 or x=10
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Answer in the comments please
Answer:
h = height reached
-16 t^2 = 1/2 g t^2 where g = 32 ft/sec^2
v t = height due to original vertical speed v
s = initial height
1. -45 = -16 t^2 + 62 t + 0 measuring height from original height
solving quadratic
2. t = 4.5 sec
3. time to reach max height = v / g = 62/32 = 1.94 sec
H (above release point) = -16 (1.94^2) + 62 * 1.94 = 60 ft
4. 2 * 1.94 = 3.88 solved in part 3
5. 1.94 solved on part 3
Check: time to fall 60 + 45 ft = 105 ft
105 = 1/2 g t^2
t = (210 / 32)^1/2 = 2.56 sec
total time = 2.56 * 1.94 = 4.5 sec time to fall + rise time
-45 = -16 * 4.5^2 + 62 * 4.5
-45 = -324 + 279 = -45 checking time to reach -45 feet using given equation