Answer:
y-9= -3(x+2)
Step-by-step explanation:
y-y1= "M" (x-x1)
y1= 9
X1= -2
Correct Question: If m∠JKM = 43, m∠MKL = (8x - 20), and m∠JKL = (10x - 11), find each measure.
1. x = ?
2. m∠MKL = ?
3. m∠JKL = ?
Answer/Step-by-step explanation:
Given:
m<JKM = 43,
m<MKL = (8x - 20),
m<JKL = (10x - 11).
Required:
1. Value of x
2. m<MKL
3. m<JKL
Solution:
1. Value of x:
m<JKL = m<MKL + m<JKM (angle addition postulate)
Therefore:

Solve for x


Subtract 8x from both sides


Add 11 to both sides


Divide both sides by 2


2. m<MKL = 8x - 20
Plug in the value of x
m<MKL = 8(17) - 20 = 136 - 20 = 116°
3. m<JKL = 10x - 11
m<JKL = 10(17) - 11 = 170 - 11 = 159°
Answer:
(4,10)
Step-by-step explanation:
7-3= 4
5=5=10
On the right side, there are
• 2•2 = 4 atoms of Nb
• 2•5 = 10 atoms of O
so among the reactants on the left, the reaction is balanced as
4 Nb + 5 O₂ → 2 Nb₂O₅
Answer:
x>-5 x ≤10
Step-by-step explanation:
-35/7=-5
7x/7=x
3x/3=x
30/3=10