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kirill115 [55]
3 years ago
6

The table shows a gophers scores for four rounds of a recent US women's open her total score was even with par what was her scor

e for the third round.
Mathematics
1 answer:
wolverine [178]3 years ago
7 0

Answer:

no table posted

Step-by-step explanation:

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quester [9]
1) 24
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7 0
3 years ago
Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br
Lina20 [59]

Answer:

The differential equation for the amount of salt A(t) in the tank at a time  t > 0 is \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

Step-by-step explanation:

We are given that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another brine solution is pumped into the tank at a rate of 3 gal/min, and when the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

The concentration of the solution entering is 4 lb/gal.

Firstly, as we know that the rate of change in the amount of salt with respect to time is given by;

\frac{dA}{dt}= \text{R}_i_n - \text{R}_o_u_t

where, \text{R}_i_n = concentration of salt in the inflow \times input rate of brine solution

and \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

So, \text{R}_i_n = 4 lb/gal \times 3 gal/min = 12 lb/gal

Now, the rate of accumulation = Rate of input of solution - Rate of output of solution

                                                = 3 gal/min - 2 gal/min

                                                = 1 gal/min.

It is stated that a large mixing tank initially holds 500 gallons of water, so after t minutes it will hold (500 + t) gallons in the tank.

So, \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

             = \frac{A(t)}{500+t} \text{ lb/gal } \times 2 \text{ gal/min} = \frac{2A(t)}{500+t} \text{ lb/min }

Now, the differential equation for the amount of salt A(t) in the tank at a time  t > 0 is given by;

= \frac{dA}{dt}=12\text{ lb/min } - \frac{2A(t)}{500+t} \text{ lb/min }

or \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

4 0
3 years ago
What statement describes the decimal equivalent of 3/ 8 ?
HACTEHA [7]

Answer:

0.375

Step-by-step explanation: All you need to do is divide 3 and 8

5 0
3 years ago
Please answer this correctly
Serggg [28]

Answer:

502 m²

Step-by-step explanation:

We require to find b before calculating the surface area.

The volume (V) of a cuboid is calculated as

V = lbh ( l is length, b is breadth and h is height )

Here V = 510, l = b, b = 10 and h = 3, thus

b × 10 × 3 = 510

30b = 510 ( divide both sides by 30 )

b = 17

--------------------------

The opposite faces of a cuboid are congruent, thus

top/bottom area = 2(17 × 10) = 2 × 170 = 340 m²

front/back area = 2(17 × 3) = 2 × 51 = 102 m²

sides area = 2(10 × 3) = 2 × 30 = 60 m²

Surface area = 340 + 102 + 60 = 502 m²

3 0
3 years ago
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