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SVETLANKA909090 [29]
3 years ago
15

What is the oxidation state of P in Ca3(PO4)2? A. -5 B. +3 C. +5 D. -3

Chemistry
1 answer:
Vlada [557]3 years ago
7 0
The answer will be A I am sure
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A self-contained system within a larger system? *
My name is Ann [436]

Answer:

subsystems.

Explanation:

A self-contained system within a larger system. system. A group of interacting or interdependent elements forming a complex whole, as in all the factors or variables in an environment or all the variables that might affect a science experiment.

4 0
3 years ago
A block of aluminium occupies a volume of 11.1 mL and weighs 43 g. What is it's density? Give answer with one decimal.
horrorfan [7]

Answer:

<h2>Density = 3.9 g/ mL</h2>

Explanation:

The density of a substance can be found by using the formula

Density =  \frac{mass}{volume}

From the question

mass = 43 g

volume = 11.1 mL

Substitute the values into the above formula and solve for the density

That's

Density =  \frac{43}{11.1}  \\  = 3.873873...

We have the final answer as

Density = 3.9 g/ mL to one decimal place

Hope this helps you

8 0
4 years ago
Which of the following is not an example of a pure element?
motikmotik
Copper wire is not an example of a pure element because although it's made by pure elements, it's not one itself. It's made by factories.

Have a nice day! :)
8 0
4 years ago
Read 2 more answers
_ is a type of liquid fuel derived from plant materials. petroleum propane biodiesel ethanol
maks197457 [2]
Ethanol is produced by the fermentation of the sugar of plants and it can be used as a fuel

in brasil they have a mass culture of using ethanol mixed with other hydrocarbons called biofuel

hope that helps 
5 0
3 years ago
Read 2 more answers
How many helium atoms are there in a helium blimp containing 535 kg of helium?
svetoff [14.1K]
<span>Helium atom's Atomic Weight = He = 4.0026 g/mol. Avagrado's number is = 6.023 x 10^23 molecules / mol. In order to find the number of atoms in 535kg of helium blimp. First we need to convert the weight of 535 kg to mol which can be done by multiplying the atomic weight of helium into present atom with respect to grams. 535 kg converted into grams ---> 535000 g There fore 535000 g X 4.0026 g/mol = 133,663 mol. (Note The grams will get cancel as per multiplication rules) Multiplying the avagadro's number with the equation we get: 133,663 mol *6.0221415 Ă— 10^23 molecules/mol= 8.04919303 Ă— 10^28 molecules. Since Helium is having 2 Atoms : 8.04919303 Ă— 10^28 molecules *2= 1.60983861 Ă— 10^29 atoms The No of Helium atoms in 535 kg of helium is 1.61 x 10^29.</span>
4 0
3 years ago
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