Answer:
<h3>The answer is 5.24 mL</h3>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula
From the question
mass = 152 g
density = 29 g/cm³
We have
We have the final answer as
<h3>5.24 mL</h3>
Hope this helps you
Explanation:
According to the law of conservation of mass, mass can neither be created nor destroyed but it can simply be transformed from one form to another.
For example, 
Mass of Na = 23 g/mol
Mass of Cl = 35.5 g/mol
Sum of mass of reactants = mass of Na + mass of Cl
= 23 + 35.5 g/mol
= 58.5 g/mol
Mass of product formed is as follows.
Mass of NaCl = mass of Na + mass of Cl
= (23 g/mol + 35.5) g/mol
= 58.5 g/mol
As mass reacted is equal to the amount of mass formed. This shows that mass is conserved.
As a result, law of conservation of mass is obeyed.
The possible number and location of all subatomic are one of them is electrically neutral, while the other has a stable electronic configuration.
<h3>What are subatomic particles?</h3>
Subatomic particles are those particles that are present inside the atoms. They are electron, neutron, and proton. They are charged particles, protons are positively charged, electrons are negatively charged and neutrons are neutral.
The protons and electrons totally contribute to the atomic mass of the elements.
Thus, the subatomic particles are electrically neutral and stable to electronic configurations.
To learn more about subatomic particles, refer to the below link:
brainly.com/question/13303285
#SPJ1
Answer:
O B. Convert the 10 g of NaCl to moles of NaCl.
Explanation:
The formula for finding the molality is m=moles of solute/kg of solvent. The solute for this question is NaCl and the solvent is water.
(10g NaCl)(1 mol NaCl/58.44g NaCl)=0.1711 mol NaCl
58.44 is the molar mass of NaCl
m=0.1711 mol NaCl/2 kg H2O
m=0.085557837
Answer:
3.076 L.
Explanation:
- The pressure is constant as it is the atmospheric pressure.
- According to Charles’ law; at constant pressure, the volume of a given quantity of a gas varies directly with its temperature.
∴ V₁T₂ = V₂T₁.
V₁ = 2.6 L & T₁ = -11 °C + 273 = 262 K.
V₂ = ??? L & T₂ = 37 °C + 273 = 310 K.
∴ V₂ = (V₁T₂) / T₁ = (2.6 L)(310 K) / (262 K) = 3.076 L.
