3 years ago

A3-9a2b + ab - 9b2 Can someone help please

Mathematics

1 answer:

Murrr4er [49]3 years ago

7 0

Answer:

(a−9b)(a2+b)

Step-by-step explanation:

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What is the answer 4(t)=50t/t^2+25

sveta [45]

Answer:

Step-by-step explanation:

50t/(t^2+25)

4(t) = [50(t^2+25)-50t(2t)]/(t^2+25)^2 = (-50t^2+1250)/(t^2+25)^2

= -50(t^2-25)/(t^2+25)^2

Roots of 4(t) are 5 and -5

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2 years ago

A science fair poster is a rectangle 3 feet long and 2 feet wide. What is the area of the poster in square inches? Be sure to in

vredina [299]

Area = length · width
Area = 3ft · 2ft
Area = 6ft²

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3 years ago

Jane wishes to bake an apple pie for dessert. The baking instructions say that she should bake the pie in an oven at a constant

pychu [463]

Answer:

A=152

K= -Ln(0.5)/14

Step-by-step explanation:

You can obtain two equations with the given information:

T(14 minutes) = 114◦C

T(28 minutes)=152◦C

Therefore, you have to replace t=14, T=114 and t=28, T=152 in the given equation:

$114=190-Ae^{-14k} (I) \\152=190-Ae^{-28k}(II)$

Applying the following property of exponentials numbers in (II):

$e^{a}.e^{b}=e^{a+b}$

Therefore $e^{-28k}$ can be written as $e^{-14k}.e^{-14k}$

$152=190-Ae^{-14k}.e^{14k}$

Replacing (I) in the previous equation:

$152=190-76e^{-14k}$

Solving for k:

Subtracting 190 both sides, dividing by -76:

$0.5=e^{-14k}$

Applying the base e logarithm both sides:

Ln(0.5)= -14k

Dividing by -14:

k= -Ln(0.5)/14

Replacing k in (I) and solving for A:

$Ae^{-14(-Ln(0.5)/14)}=76\\Ae^{Ln(0.5)} =76\\A(0.5)=76$

Dividing by 0.5

A=152

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3 years ago

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GenaCL600 [577]

10
I think that’s it hope that helps

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2 years ago

Read 2 more answers

Write 9.159 x 108 in decimal form.

Mars2501 [29]

Answer: 989.172

Step-by-step explanation:

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2 years ago