Number of dimes collected is 339 and number of nickels collected is 113
<em><u>Solution:</u></em>
Given that There is a total of $39.55
There are 3 times as many dimes as nickels
To find: Number of dimes and nickels collected
Let "d" be the number of dimes collected
Let "n" be the number of nickels collected
We know that,
1 dime = $ 0.10
1 nickel = $ 0.05
From given information,
There are 3 times as many dimes as nickels
So, we get
Number of dimes = 3(number of nickels)
d = 3n
Given that there is total of $ 39.55
number of dimes collected x value of 1 dime + number of nickels collected x value of 1 nickel = $ 39.55
Substitute n = 113 in d = 3n
<em><u>Summarizing the results:</u></em>
number of dimes collected = 339
number of nickels collected = 113
1.
a. your answer is correct
b. 60 and hndreths=60.08
c. 16 and 8 thousanths=16.008
d. 60 and 8 tenths=60.8
e. your answer is correct
f. your answer is correct
2. 16.207, 6.9, 16.19, 16.26
so the greatest is obviously one of the 16's
compare
16.207, 16.190, 16.260
obviously, the order is 16.260,16.207,16.190
then the last one is 6.9 so the order is 16.26,16.207, 16.19, 6.9 and the numbers in order is 2,4,3,1
3. I can't see the puzzle that well, but 11.88 is more than 11.50 since 0.88 is more than 0.50
4. can't see the puzzle that mmuch
hundreths is 0.0x x is the hundrreths since exg 1/100=1 hundreths=0.01
5. remember if the number is more than five round up and if less than 4 round down so
10.5, 10.6, 10.7 10.8 10.9 10.1 10.2 10.3 10.4 would work
6. tenth=0.8 so the numbers could be 17.81, 17.82 17,83
7.rembmber the decimal places and line them up so again
6.081, 6.082 6.083 and so on
8. 1/2=0.5 or 0.50000
9. the greatest decimal
first find the greatest whole number
60
then find all the 60's and read from left to right the numbers after the decimal, the biggest number to the left is bigger, if they are the same, move one place to the right and count again
10. I can't seee the puzzzle very clearly but hte answer is pirates
First, we establish
our hypothesis:
<span>Null hypothesis H0: μ = $1.00 </span>
Alternative hypothesis
Ha: μ ≠ $1.00
<span>Let’s say X = the sample average cost of a daily newspaper
= 0.96</span>
u = population mean
cost = 1.00
S = sample standard
deviation = 0.18
Calculating for z
value:
z = (X – u) / S
z = (0.96 – 1) / 0.18
z = – 0.222
From the standard
distribution table at this z value, p-value = 0.4129
Since alpha = 0.01,
the decision therefore is:
<span>Do not reject the null
hypothesis because the p-value is greater than 0.01. There is enough evidence
to support the claim that the mean cost of newspapers is $1. </span>
Answer:
The required rate of interest = 14.285%
Step-by-step explanation:
Here, The principal amount = 7,000
The final paid amount = 9,000
Time = 2 years
Let us assume the rate of interest = R
Now, Simple Interest = Amount - Principal
= 9,000 - 7,000 = 2,000
So, the SI on the given principal for 2 years = 2,000
or, R = 14.285%
Hence, the required rate of interest = 14.285%
