Can I get a new photo, I would gladly answer all of them for you
Answer:
68x + 36y
General Formulas and Concepts:
- Order of Operations: BPEMDAS
- Combining like terms
Step-by-step explanation:
<u>Step 1: Define expression</u>
(19x + 4y) + (49x + 32y)
<u>Step 2: Simplify expression</u>
- Combine like terms (x): 68x + 4y + 32y
- Combine like terms (y): 68x + 36y
Answer:
The second time when Luiza reaches a height of 1.2 m = 2 08 s
Step-by-step explanation:
Complete Question
Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.
H(t) = -0.6 cos (2pi/2.5)t + 1.5.
What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.
Solution
Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as
H(t) = -0.6cos(2π/2.5)t + 1.5
What is t when H = 1.2 m
1.2 = -0.6cos(2π/2.5)t + 1.5
0.6cos(2π/2.5)t = 1.2 - 1.5 = -0.3
Cos (2π/2.5)t = (0.3/0.6) = 0.5
Note that in radians,
Cos (π/3) = 0.5
This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,
Cos (5π/3) = 0.5
So,
Cos (2π/2.5)t = Cos (5π/3)
(2π/2.5)t = (5π/3)
(2/2.5) × t = (5/3)
t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.
Hope this Helps!!!
I think your answer is ( B )
Answer:
ab=32
Step-by-step explanation:
ab:bc
4:3
abc= 56
4+3=7
56÷7=8
ab= 8x4=32
bc=8x3=24 #
