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sineoko [7]
2 years ago
6

Given PQ = y, RS = 4y - 15, QR = 2 +6, and PS = 4a - 6, solve for the length of RS and QR.

Mathematics
1 answer:
Anna11 [10]2 years ago
3 0

Answer:

Check pdf

Step-by-step explanation:

Download pdf
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Solve 2/3x> 8 or 2/3x< 4
grigory [225]

Answer:

x > 12

Answer for 2/3>8

8 0
2 years ago
Read 2 more answers
A 4​-ft vertical post casts a 12​-in shadow at the same time a nearby cell phone tower casts a 122​-ft shadow. How tall is the c
zepelin [54]

Answer:

the cell phone tower is 488 ft

Step-by-step explanation:


change 12 in = 1ft

4ft                            x ft

------------------- =   ----------------

1ft  shadow           122 ft shadow


using cross products

4 * 122 = 1 * x

488 = x

3 0
2 years ago
Hannah is deciding between two truck rental companies. Company A charges an initial fee of $30 for the rental plus $2 per mile d
Degger [83]

Answer:

Hannah is deciding between two truck rental companies. Company A charges an initial fee of $30 for the rental plus $2 per mile driven. Company B charges an initial fee of $100 for the rental plus $1 per mile driven. Let AA represent the amount Company A would charge if Hannah drives xx miles, and let BB represent the amount Company B would charge if Hannah drives xx miles. Write an equation for each situation, in terms of x,x, and determine the interval of miles driven, x,x, for which Company A is cheaper than Company B.

5 0
3 years ago
A radioactive substance decays exponentially: The mass at time t is m(t) = m(0)ekt, where m(0) is the initial mass and k is a ne
velikii [3]

Answer:

M = 1/0.000121 = 8264.5 years

Step-by-step explanation:

M = − k ∫∞₀ teᵏᵗdt

To obtain this mean life, we'll use integration by parts to integrate the function ∫ teᵏᵗdt

∫udv = uv - ∫ vdu

u = t

du/dt = 1

du = dt

∫ dv = ∫ eᵏᵗdt

v = eᵏᵗ/k

∫udv = ∫ teᵏᵗdt

uv = teᵏᵗ/k

∫ vdu = eᵏᵗ/k

∫ teᵏᵗdt = (teᵏᵗ/k) - ∫eᵏᵗ/k

But, ∫eᵏᵗ/k = (1/k) ∫eᵏᵗ = (1/k²) eᵏᵗ = eᵏᵗ/k²

∫ teᵏᵗdt = (teᵏᵗ/k) - eᵏᵗ/k²

The rest of the calculation is done on paper in the image attached to this question

3 0
3 years ago
What is the simplified form of the following expression? 2√27+√12-3√3-2√12
LiRa [457]

Answer:

√3

Step-by-step explanation:

The given expression to be simplified is

2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}

but

2 \sqrt{27}=2\sqrt{9 \times 3}=2 \times \sqrt{9}\times \sqrt{3}=2 \times 3 \times\sqrt{3}=6 \sqrt{3}

\sqrt{12}=\sqrt{4\times3}= \sqrt{4}\times \sqrt{3}=2\sqrt{3}

Since √12=2√3,this implies that,

2\sqrt{12}=2\times2\sqrt{3}=4 \sqrt{3}

Therefore,

2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}=6\sqrt{3}+2\sqrt{3}-3 \sqrt{3} -4\sqrt{3}

=(6+2-3-4)\sqrt{3}

=\sqrt{3}

The simplified form of ,

2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12} is √3

8 0
2 years ago
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