Given PQ = y, RS = 4y - 15, QR = 2 +6, and PS = 4a - 6, solve for the
length of RS and QR.
1 answer:
Answer:
Check pdf
Step-by-step explanation:
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I got -19/655 and i know for sure this isnt the correct answer.
Answer:
(4x + 2)° = (6x -10)°
4x + 2 = 6x - 10
4x -6x = -10 -2
-2x = -12
x = <u>-</u><u>12</u>
-2
x = 6°
15 gggggggggggggggggggggg
Answer:
A =4πr2
Step-by-step explanation:
Regroup terms
2(x + 2) = 1
Divided both sides by 2
x + 2 = 1/2
Subtract 2 from both sides
x = 1/2 - 2
Simplify 1/2 - 2 to -3/2
<u>x = -3/2</u>
