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LuckyWell [14K]
3 years ago
5

Consider a disk that rotates at 3600 rpm. The seek time to move the head between adjacent tracks is 2 ms. There are 32 sectors p

er track, which are stored in linear order from sector 0 through sector 31. The head sees the sectors in ascending order. Assume the read/write head is positioned at the start of sector 1 on track 8. There is a main memory buffer large enough to hold an entire track. Data is transferred between disk locations by reading from the source track into the main memory buffer and then writing the data from the buffer to the target track. a. How long will it take to transfer sector 1 on track 8 to sector 1 on track 9
Computers and Technology
1 answer:
jasenka [17]3 years ago
3 0

Answer:

19.71 ms

Explanation:

The disk rotates at 3600 rpm, hence the time for one revolution = 60 / 3600 rpm = 16.67 ms.

Hence time to read or write on a sector = time for one revolution / number of sectors per track = 16.67 ms / 32 sectors = 0.52 ms

Head movement time from track 8 to track  9 = seek time = 2 ms

rotation time to head up sector 1 on track 8 to sector 1 on track 9 = 16.67 * 31/32 = 16.15 ms

The total time = sector read time +head movement time + rotational delay + sector write time = 0.52 ms + 2 ms + 16.15 ms + 0.52 ms = 19.19 ms

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Answer:

Check the explanation

Explanation:

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import java.util.Scanner;

class linearsearch

{

  public static void main(String args[])

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     int count, number, item, arr[];

     

     Scanner console = new Scanner(System.in);

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     number = console.nextInt();

   

     arr = new int[number];

     System.out.println("Enter " + number + " ");

     

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       arr[count] = console.nextInt();

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     item = console.nextInt();

     for (count = 0; count < number; count++)

     {

        if (arr[count] == item)

        {

          System.out.println(item+" present at "+(count+1));

         

          break;

        }

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Kindly check the first attached image below for the code output.

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public class selectionsort {

   public static void selectionsort(int[] array){

       for (int i = 0; i < array.length - 1; i++)

       {

           int ind = i;

           for (int j = i + 1; j < array.length; j++){

               if (array[j] < array[ind]){

                   ind = j;

               }

           }

           int smaller_number = array[ind];  

           array[ind] = array[i];

           array[i] = smaller_number;

       }

   }

     

   public static void main(String a[]){

       int[] arr = {9,94,4,2,43,18,32,12};

       System.out.println("Before Selection Sort");

       for(int i:arr){

           System.out.print(i+" ");

       }

       System.out.println();

         

       selectionsort(arr);

       

       System.out.println("After Selection Sort");

       for(int i:arr){

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       }

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Kindly check the second attached image below for the code output.

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                }

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       }

}  

Kindly check the third attached image below for the code output.

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     if (lw > hg) return -1;

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     for (int i = 0; i < ar.length; i++)

        System.out.print(obj.binarySearch(ar,

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     System.out.println();

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Kindly check the fourth attached image below for the code output

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