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Advocard [28]
3 years ago
8

____________________________ and _________________________ are 2 negative impacts of the internet on businesses.

Computers and Technology
1 answer:
Bogdan [553]3 years ago
7 0

Answer:

i no you its me remember and the answer is b.

Explanation:

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Wice each lunar month, all year long, these tides occur. Whenever the Moon, Earth and Sun are aligned, the gravitational pull of
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E)   none of those   Adds; Spring
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Which of the following processes allows animators to use computers to input human movement that can later be transformed to crea
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Motion Capture. "it's a combination of rotoscoping with newer computer technology, allowing people to use live footage as the basis for animation without having to go through the process of drawing over it." -scienceworld .ca
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Translate the following MIPS code to C. Assume that the variables f, g, h, i, and j are assigned to registers $s0, $s1, $s2, $s3
Romashka [77]

Answer:

f = 2 * (&A[0])

See explaination for the details.

Explanation:

The registers $s0, $s1, $s2, $s3, and $s4 have values of the variables f, g, h, i, and j respectively. The register $s6 stores the base address of the array A and the register $s7 stores the base address of the array B. The given MIPS code can be converted into the C code as follows:

The first instruction addi $t0, $s6, 4 adding 4 to the base address of the array A and stores it into the register $t0.

Explanation:

If 4 is added to the base address of the array A, then it becomes the address of the second element of the array A i.e., &A[1] and address of A[1] is stored into the register $t0.

C statement:

$t0 = $s6 + 4

$t0 = &A[1]

The second instruction add $t1, $s6, $0 adding the value of the register $0 i.e., 32 0’s to the base address of the array A and stores the result into the register $t1.

Explanation:

Adding 32 0’s into the base address of the array A does not change the base address. The base address of the array i.e., &A[0] is stored into the register $t1.

C statement:

$t1 = $s6 + $0

$t1 = $s6

$t1 = &A[0]

The third instruction sw $t1, 0($t0) stores the value of the register $t1 into the memory address (0 + $t0).

Explanation:

The register $t0 has the address of the second element of the array A (A[1]) and adding 0 to this address will make it to point to the second element of the array i.e., A[1].

C statement:

($t0 + 0) = A[1]

A[1] = $t1

A[1] = &A[0]

The fourth instruction lw $t0, 0($t0) load the value at the address ($t0 + 0) into the register $t0.

Explanation:

The memory address ($t0 + 0) has the value stored at the address of the second element of the array i.e., A[1] and it is loaded into the register $t0.

C statement:

$t0 = ($t0 + 0)

$t0 = A[1]

$t0 = &A[0]

The fifth instruction add $s0, $t1, $t0 adds the value of the registers $t1 and $t0 and stores the result into the register $s0.

Explanation:

The register $s0 has the value of the variable f. The addition of the values stored in the regsters $t0 and $t1 will be assigned to the variable f.

C statement:

$s0 = $t1 + $t0

$s0 = &A[0] + &A[0]

f = 2 * (&A[0])

The final C code corresponding to the MIPS code will be f = 2 * (&A[0]) or f = 2 * A where A is the base address of the array.

3 0
3 years ago
1. Write a program that declares an array named alpha with 50 components of the type double. Initialize the array so that the fi
Aleksandr [31]

Answer:

Explanation:

1. Write a program that declares an array named alpha with 50 components of the type double. Initialize the array so that the first 25 components are equal to the square of the counter (or index) variable and the last 25 components are equal to three times the index variable.  

  double alpha[50];

   for (int i=0;i<25;i++)

   {

       alpha[i]=i*i;

       alpha[i+25]=(i+25)*3;

  }

2. Output the array so that exactly ten elements per line are printed.  

   for (int i=0;i<50;i++)

   {

       cout<<i+1<<". "<<alpha[i]<<" ";

       if (((i+1)%10)==0)

       {

           cout<<endl;

       }

   }

3. Run your program again, but this time change the code so that the array is filled with random numbers between 1 and 100.  

   double alpha[50];

   for (int i=0;i<50;i++)

   {

       alpha[i]=rand()%101;

   }

   for (int i=0;i<50;i++)

   {

       cout<<i+1<<". "<<alpha[i]<<" ";

       if (((i+1)%10)==0)

       {

           cout<<endl;

       }

   }

4. Write the code that computes and prints the average of elements of the array.  

   double alpha[50],temp=0;

   for (int i=0;i<50;i++)

   {

       alpha[i]=rand()%101;

       temp+=alpha[i];

   }

   cout<<"Average :"<<(temp/50);

5. Write the code that that prints out how many of the elements are EXACTLY equal to 100.

   double alpha[50],temp=0;

   for (int i=0;i<50;i++)

   {

       alpha[i]=rand()%101;

       if(alpha[i]==100)

       {

           temp++;

       }

   }

   cout<<"Elements Exacctly 100 :"<<temp;

Please note:  If you put  each of above code to the place below comment  it will run perfectly after compiling

#include <iostream>

using namespace std;

int main()

{

   // If you put  each of above code here it will run perfectly after compiling

   return 0;

}

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3 years ago
What should you do when an error message pops up on the screen?
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D.) Write down the error message and research the cause based on the message.
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