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lbvjy [14]
3 years ago
7

If 30% of a number, n, is 120, what is 82% of n?

Mathematics
2 answers:
sp2606 [1]3 years ago
8 0

Answer:

82% of n = 328

Step-by-step explanation:

n = 400

400 x .3 = 120

400 x .82 = 328

Hopefully this helped you:)

Naya [18.7K]3 years ago
5 0

Answer:

1.28

Step-by-step explanation:

I did the math.

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Vinvika [58]
£1.80 divided by 4 =0.45...
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3 years ago
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I need help with number 16 please
Sunny_sXe [5.5K]
A) The graph is misleading because it dosent give the number of students, it gives percentages.

b) A more appropriate way to display data would be a line graph because it shows the number of students favorite sports.
8 0
3 years ago
an inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a
viktelen [127]

Answer:

the rate of change of the water depth when the water depth is 10 ft is;  \mathbf{\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi} \  \ ft/s}

Step-by-step explanation:

Given that:

the inverted conical water tank with a height of 20 ft and a radius of 8 ft  is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.

We are meant to find the  rate of change of the water depth when the water depth is 10 ft.

The diagrammatic expression below clearly interprets the question.

From the image below, assuming h = the depth of the tank at  a time t and r = radius of the cone shaped at a time t

Then the similar triangles  ΔOCD and ΔOAB is as follows:

\dfrac{h}{r}= \dfrac{20}{8}    ( similar triangle property)

\dfrac{h}{r}= \dfrac{5}{2}

\dfrac{h}{r}= 2.5

h = 2.5r

r = \dfrac{h}{2.5}

The volume of the water in the tank is represented by the equation:

V = \dfrac{1}{3} \pi r^2 h

V = \dfrac{1}{3} \pi (\dfrac{h^2}{6.25}) h

V = \dfrac{1}{18.75} \pi \ h^3

The rate of change of the water depth  is :

\dfrac{dv}{dt}= \dfrac{\pi r^2}{6.25}\  \dfrac{dh}{dt}

Since the water is drained  through a hole in the vertex (bottom) at a rate of 4 ft^3/sec

Then,

\dfrac{dv}{dt}= - 4  \ ft^3/sec

Therefore,

-4 = \dfrac{\pi r^2}{6.25}\  \dfrac{dh}{dt}

the rate of change of the water at depth h = 10 ft is:

-4 = \dfrac{ 100 \ \pi }{6.25}\  \dfrac{dh}{dt}

100 \pi \dfrac{dh}{dt}  = -4 \times 6.25

100  \pi \dfrac{dh}{dt}  = -25

\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi}

Thus, the rate of change of the water depth when the water depth is 10 ft is;  \mathtt{\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi} \  \ ft/s}

4 0
4 years ago
Find the length of the missing side, x=
Paladinen [302]

{x}^{2}  +  {11.9}^{2}  =   {14.7}^{2}  \\ x =  \sqrt{ {14.7}^{2}  -  {11.9}^{2} }  \\  x =  \sqrt{74.48}  \\  x =  8.6301796042...

Answer: 9 or 8.6

  • I don't know, need I round to 8.6 or 9, so you can try both answers
8 0
4 years ago
NEED HELP ASAP PLEASE!!!!!!!!!!1
Anna71 [15]
So the formula is πrL

so
π×8×5
125.6cm2

hopes that correct :)
7 0
3 years ago
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