We have been given in a cohort of 35 graduating students, there are three different prizes to be awarded. We are asked that in how many different ways could the prizes be awarded, if no student can receive more than one prize.
To solve this problem we will use permutations.

We know that formula for permutations is given as

On substituting the given values in the formula we get,


Therefore, there are 39270 ways in which prizes can be awarded.
In all poe ate 2/3 of the left overs
5: six twelfths is one half
6: eight tenths is four fifths
7: four eighths is one half
8: ten tenths is two halves
9: two sixths is one third
10: one quarter, because you divide the top and bottom number by 3
method:
take the first one - four eighths, which is 4/8
the question gives you what to divide them by, 4, so u divide both the top number and bottom number to get 1/2, which is one half :)
Answer:
Step-by-step explanation:
Comment
The angle supplementary to x and 3x are equal.
Supplementary angles = 180
Solution
x + 3x = 180
4x = 180 Divide by 4
4x/4 = 180/4
x = 45
The angle supplementary to x is 3x
3x = 3*45
3x = 135
This angle is vertically opposite y. Vertically opposite angles are equal. So y = 135
Answer
x = 45
y = 135
-6 is the answer since 6*-1 is -6