Distance of bank from yuri's house=(5/6)*(2/5)=2/6=1/3 mile
Answer:
<h2>The distance from the pitcher's mound and to second base is 37.99 approximately.</h2>
Step-by-step explanation:
The diamond is a square, which in this case has 50 feet long each side, and from home to pitcher is 38 feet. Notice that home is a vertex of the square and the pitcher's mound is the intersection of the diagonals, where they cut half.
We can find the distance from the pitcher to first base using Pythagorean's Theorem, where 50 feet is the hypothenuse.

Therefore, the distance from the pitcher to first base is 32.5 feet, approximately.
Now, we can use again Pythagorean's Theorem to find the distance from pitcher to second base, where the hypothenuse is 50 feet.

Therefore, the distance from the pitcher's mound and to second base is 37.99 approximately.
<em>(this results make sense, because the diagonals of a square intersect at half, that means all bases have the same distance from pitcher's mound, so the second way to find the distance asked in the question is just using theory)</em>
Answer: x = 3.5
Step-by-step explanation:
Answer:
Probability ball: white - P(W)P(W);
Probability ball: even - P(E)P(E);
Probability ball: white and even - P(W&E).
Probability ball picked being white or even: P(WorE)=P(W)+P(E)-P(W&E).
(1) The probability that the ball will both be white and have an even number painted on it is 0 --> P(W&E)=0 (no white ball with even number) --> P(WorE)=P(W)+P(E)−0P(WorE)=P(W)+P(E)−0. Not sufficient
(2) The probability that the ball will be white minus the probability that the ball will have an even number painted on it is 0.2 --> P(W)−P(E)=0.2P(W)−P(E)=0.2, multiple values are possible for P(W)P(W) and P(E)P(E) (0.6 and 0.4 OR 0.4 and 0.2). Can not determine P(WorE)P(WorE).
(1)+(2) P(W&E)=0 and P(W)−P(E)=0.2P(W)−P(E)=0.2 --> P(WorE)=2P(E)+0.2P(WorE)=2P(E)+0.2 --> multiple answers are possible, for instance: if P(E)=0.4P(E)=0.4 (10 even balls) then P(WorE)=1P(WorE)=1 BUT if P(E)=0.2P(E)=0.2 (5 even balls) then P(WorE)=0.6P(WorE)=0.6. Not sufficient.
Answer: E.
Y = -8/3x + 2...slope here is -8/3. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal of the slope -8/3, u just flip the slope and change the sign. So our perpendicular line will have a slope of 3/8.
y = mx + b
slope(m) = 3/8
(32,6)...x = 32 and y = 6
now we sub and find b, the y int
6 = 3/8(32) + b
6 = 12 + b
6 - 12 = b
-6 = b
so ur perpendicular equation is : y = 3/8x - 6