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3 years ago

-7=2+ w Help please

Mathematics

1 answer:

ziro4ka [17]3 years ago

5 0

Answer:

w= -9 :)

Step-by-step explanation:

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4x+1=2x-5 what is the answer

LekaFEV [45]

Answer:

-3

Step-by-step explanation:

4x+1=2x-5

-1 -1

4x= 2x-6

-2x -2x

2x=-6

/2 /2

x=-3

6 0

2 years ago

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How many minutes have elapsed between 7:22 pm and 7:36 pm?

Nutka1998 [239]

The hour has stayed the same. 36-22 is 14. That's 14 minutes between.

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3 years ago

Find derivative problem<br> Find B’(6)

dalvyx [7]

Answer:

$B^\prime(6) \approx -28.17$

Step-by-step explanation:

We have:

$\displaystyle B(t)=24.6\sin(\frac{\pi t}{10})(8-t)$

And we want to find B’(6).

So, we will need to find B(t) first. To do so, we will take the derivative of both sides with respect to x. Hence:

$\displaystyle B^\prime(t)=\frac{d}{dt}[24.6\sin(\frac{\pi t}{10})(8-t)]$

We can move the constant outside:

$\displaystyle B^\prime(t)=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)]$

Now, we will utilize the product rule. The product rule is:

$(uv)^\prime=u^\prime v+u v^\prime$

We will let:

$\displaystyle u=\sin(\frac{\pi t}{10})\text{ and } \\ \\ v=8-t$

Then:

$\displaystyle u^\prime=\frac{\pi}{10}\cos(\frac{\pi t}{10})\text{ and } \\ \\ v^\prime= -1$

(The derivative of u was determined using the chain rule.)

Then it follows that:

$\displaystyle \begin{aligned} B^\prime(t)&=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)] \\ \\ &=24.6[(\frac{\pi}{10}\cos(\frac{\pi t}{10}))(8-t) - \sin(\frac{\pi t}{10})] \end{aligned}$

Therefore:

$\displaystyle B^\prime(6) =24.6[(\frac{\pi}{10}\cos(\frac{\pi (6)}{10}))(8-(6))- \sin(\frac{\pi (6)}{10})]$

By simplification:

$\displaystyle B^\prime(6)=24.6 [\frac{\pi}{10}\cos(\frac{3\pi}{5})(2)-\sin(\frac{3\pi}{5})] \approx -28.17$

So, the slope of the tangent line to the point (6, B(6)) is -28.17.

5 0

3 years ago

10 + 9 • (−3) 2− (−1 + 8)

Vitek1552 [10]

Answer:

-51

Step-by-step explanation:

PEMDAS suggests you start with parenthesis

10+9•(-3)2-(7)

10-(27)2-(7)

10-54-7

-51

3 0

2 years ago

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if each side of a square classroom is 25 feet then what is the perimeter of the room? what is the area of the floor of the room?

Svetllana [295]

Answer:

P = 100

Area = 625

Step-by-step explanation:

Area = s^2

sqrt(area) = sqrt(s^2)

area = 25*25

sqrt(25*25) = sqrt(s^2)

s = 25

P = 4*s

P = 4 * 25

P = 100

Area = s^2

s = 25

Area = 25^2

Area = 625

4 0

2 years ago