Ask question

Ask question

All categories

Mandarinka [93]

3 years ago

12

The graph shows the motion of two cars starting at different places on a highway. Their speeds can be compared by comparing the

steepness of the graphed lines.
Use the drop-down menus to complete the statements.

1 answer:

Mars2501 [29]3 years ago

8 0

Answer:the dot goes in in the blue line in 0 and 150 just like the blue line

Step-by-step explanation:I hope you get what I mean

You might be interested in

Which equation can be used to solve for in the following diagram?

Ivahew [28]

Answer:

the Answer is 3x+12)+X=180

5 0

3 years ago

A parking lot holds 42 cars. There are 26 cars in the lot already. Which inequality can be solved to show all the numbers of car

MissTica

16 parking lots still left.

6 0

3 years ago

Read 2 more answers

• The total rise of a set of stairs is 81.125". If there are 11 risers, what is the height of

patriot [66]

Answer:

7.375".

Step-by-step explanation:

That would be 81.125 / 11

= 7.375 ".

3 0

3 years ago

PLEASE ANSWER AND HELP

ra1l [238]

She must save $91.80.

7 0

3 years ago

Multiply the polynomials.<br> (4x- + 4x + 6)(7x + 5)

SashulF [63]

$\implies {\blue {\boxed {\boxed {\purple {\sf { \: 28 {x}^{3} + 48 {x}^{2} + 62x + 30}}}}}}$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}$

$(4 {x}^{2} + 4x + 6)(7x + 5)$

$= \: 7x(4 {x}^{2} + 4x + 6) + 5(4 {x}^{2} + 4x + 6)$

$= \: 28 {x}^{3} + 28 {x}^{2} + 42x + 20 {x}^{2} + 20x + 30$

Combining like terms, we have

$= \: 28 {x}^{3} + (28 {x}^{2} + 20 {x}^{2} ) + (42x + 20x) + 30$

$= \: 28 {x}^{3} + 48 {x}^{2} + 62x + 30$

$\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}$

3 0

3 years ago