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Zanzabum
2 years ago
12

9. On a math test with 52 questions, Kim solved 3/4 of the questions correctly. How many questions did Kim solve

Mathematics
1 answer:
kirill115 [55]2 years ago
7 0

Answer: Kim got 13 questions wrong.

Step-by-step explanation: First find how many questions were 75% of 52 questions since 3/4 is equal to 75%. Then subtract that amount (which is 39) from 52 and you get 13.

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Points A, B, and C are collinear, and B lies
olya-2409 [2.1K]

Answer:

BC = 30

Step-by-step explanation:

If the three points are collinear, it means they lie on the same straight line.

Now B lies between A and C

By mathematical convention;

AC = AB + BC

This means;

48 = 2x + 2 + 3x + 6

48 = 5x + 8

48-8 = 5x

5x = 40

x = 40/5

x = 8

From the question BC = 3x + 6

Substitute the value of x; 3(8) + 6 = 24 + 6 = 30

3 0
2 years ago
Find the range for f(x)=8x-3,given the domain is {-2,4,8,10}
Setler [38]

Answer:

-19, 29, 61, 77

Step-by-step explanation:

Put the domain numbers as a solution for x. May or may not be right. Sorry if it's wrong...

6 0
3 years ago
Read 2 more answers
Guys, Can you please help me with these questions
MakcuM [25]

Answer:

a) w^{13} x^{5} y^{6}

b) \frac{x}{3y^{6} }

Step-by-step explanation:

a) (w^{2} xy^{3} )^{2}(w^{3}x )^{3}

1. Distribute the second power (2) outside the first pair of parenthesis:

(w^{2(2)} x^{2} y^{3(2)} )

= w^{4} x^{2} y^{6} (w^{3}x )^{3}

2. Distribute the third power (3) outside the second pair of parenthesis:

(w^{3(3)} x^{3} )

= w^{4} x^{2} y^{6} w^{9} x^{3}

3. Combine like terms:

w^{13} x^{5} y^{6}

--------------------------------------------

b) \frac{2x^{2} y^{5} }{6xy^{11} }

1. Factor the number 6 (= 2 · 3):

\frac{2x^{2} y^{5} }{2(3)xy^{11} }

2. Cancel the common factor (2):

\frac{x^{2} y^{5} }{3xy^{11} }

3. Cancel out xy^{5} in the numerator an denominator:

\frac{x}{3y^{6} }

hope this helps!

4 0
2 years ago
Find the value of x such that 365 based seven + 43 based x = 217 based 10.
Pepsi [2]

We need to find the base x in the following equation:

365_7+43_x=217_{10}

First, lets convert 365 from base 7 to base 10. This is given by

365_7=3\times7^2+6\times7^1+5\times7^0

where the upperindex denotes the position of eah number. This gives

\begin{gathered} 365_7=3\times49+6\times7+5\times1 \\ 365_7=147+42+5 \\ 365_7=194_{10} \end{gathered}

that is, 365 based 7 is equal to 194 bases 10.

Now, lets do the same for 43 based x. Lets convert 43 based x to base 10:

43_x=4\times x^1+3\times x^0

where again, the superindex 0 and 1 denote the position 0 and 1 in the number 43. This gives

43_x=(4x+3)_{10}

Now, we have all number in base 10. Then, our first equation can be written in base 10 as

194_{10}+(4x+3)_{10}=217_{10}

For simplicity, we can omit the 10 and get

194+4x+3=217

so, we can solve this equation for x. By combining similar terms. we have

197+4x=217

and by moving 197 to the right hand side, we obtain

\begin{gathered} 4x=217-197 \\ 4x=20 \end{gathered}

Finally, we get

\begin{gathered} x=\frac{20}{4} \\ x=5 \end{gathered}

Therefore, the solution is x=5

8 0
10 months ago
Help please please help…….
olga nikolaevna [1]

Answer:

Choice A

Step-by-step explanation:

y-intercept = -3

double-checked on calculator

8 0
2 years ago
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