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soldi70 [24.7K]
3 years ago
6

In the number 8,234,091,257 which digit is in the billions place

Mathematics
1 answer:
jenyasd209 [6]3 years ago
3 0

Answer:

8

Step-by-step explanation: this is easy lol

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HELP PLSSS I DONT REMEMBER!!
Tatiana [17]

Answer:

8x-31 = 2x+92

Step-by-step explanation:

The angles are corresponding angles and corresponding angles are equal

8x-31 = 2x+92

8 0
2 years ago
Michael put the following items in his shopping basket
lesantik [10]

Answer:

c. $9

Step-by-step explanation:

$3.98 + $4.19 + $0.79 = $8.96

Round to the nearest whole number which would be 9

4 0
3 years ago
Solve.... 4n- 9= 2 (5+ 2n)
timama [110]

Answer:

Step-by-step explanation:

Here you go mate

Use PEMDAS

Parenthesis,Exponent,Multiplication,Division,Addition,Subtraction

Step 1

4n-9=2(5+2n)  Equation/Question

Step 2

4n-9=2(5+2n)  Remove parenthesis

4n-9=4n+10

Step 3

4n-9=4n+10  Subtract 4n to sides

-9=10

Step 4

-9=10  Add 9

0=19

Answer

No solutions

Hope this helps

3 0
3 years ago
12.5 percent of what number is 24
irina [24]

24 : 12.5/100 = 24 * 100/12.5 = 192;
3 0
3 years ago
A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. ​(a) What must be true
valentina_108 [34]

Answer:

(a) The distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b) The value of P(\bar X is 0.7642.

(c) The value of P(\bar X\geq 69.1) is 0.3670.

Step-by-step explanation:

A random sample of size <em>n</em> = 10 is selected from a population.

Let the population be made up of the random variable <em>X</em>.

The mean and standard deviation of <em>X</em> are:

\mu=68\\\sigma=15

(a)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. <em>n</em> = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

\mu_{\bar x}=\mu=68

And the standard deviation of the distribution of the sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{15}{\sqrt{10}}=4.74

Thus, the distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b)

Compute the value of P(\bar X as follows:

P(\bar X

                    =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the value of P(\bar X is 0.7642.

(c)

Compute the value of P(\bar X\geq 69.1) as follows:

Apply continuity correction as follows:

P(\bar X\geq 69.1)=P(\bar X> 69.1+0.5)

                    =P(\bar X>69.6)

                    =P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{69.6-68}{4.74})

                    =P(Z>0.34)\\=1-P(Z

Thus, the value of P(\bar X\geq 69.1) is 0.3670.

7 0
3 years ago
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