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3 years ago

What is the solution to 0.4(12 – 3x) = 0.3(12x - 16)?

Mathematics

1 answer:

ser-zykov [4K]3 years ago

8 0

Answer:

You need to simplify 0.3(12x + -16) = 0.4(12 + -3x)

Step-by-step explanation:

Reorder the terms:

0.3(-16 + 12x) = 0.4(12 + -3x) (-16 * 0.3 + 12x * 0.3) = 0.4(12 + -3x) (-4.8 + 3.6x) = 0.4(12 + -3x) -4.8 + 3.6x = (12 * 0.4 + -3x * 0.4) -4.8 + 3.6x = (4.8 + -1.2x)

Solving -4.8 + 3.6x = 4.8 + -1.2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '1.2x' to each side of the equation. -4.8 + 3.6x + 1.2x = 4.8 + -1.2x + 1.2x

Combine like terms: 3.6x + 1.2x = 4.8x -4.8 + 4.8x = 4.8 + -1.2x + 1.2x

Combine like terms: -1.2x + 1.2x = 0.0 -4.8 + 4.8x = 4.8 + 0.0 -4.8 + 4.8x = 4.8 Add '4.8' to each side of the equation. -4.8 + 4.8 + 4.8x = 4.8 + 4.8

Combine like terms: -4.8 + 4.8 = 0.0 0.0 + 4.8x = 4.8 + 4.8 4.8x = 4.8 + 4.8

Combine like terms: 4.8 + 4.8 = 9.6 4.8x = 9.6 Divide each side by '4.8'. x = 2

Simplifying x = 2

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3 years ago

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Answer:

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Step-by-step explanation:

Hello, please consider the following.

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Step-by-step explanation:

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3 years ago

A large population of variable x is characterized by its known mean value of 6.1 units and a standard deviation of 1.0 units and

scoundrel [369]

Answer:

-6.134 to +6.134

Step-by-step explanation:

given that a large population of variable x is characterized by its known mean value of 6.1 units and a standard deviation of 1.0 units and a normal distribution

X is Normal with mean =6.1 and std dev = 1 unit

We are to determine the range of values containing 70% of the population of x

We know that normal distribution curve is bell shaped symmetrical about the mean.

So to find 70% range we can use 35% on either side of the mean

Using std normal distribution table the value of z for which probability from 0 to z is 0.35 is 1.034

Hence corresponding x value is

$x=6.1+1.034*1\\x=6.134$