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gizmo_the_mogwai [7]
3 years ago
13

Using the number line above, select the number that would be the opposite of Point T.

Mathematics
1 answer:
iris [78.8K]3 years ago
7 0

Answer:-9

Step-by-step explanation:

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7t-3t+4t-5t show working​
sukhopar [10]

Answer:

3t

Step-by-step explanation:

7t-3t+4t-5t

Combine like terms

7t -3t = 4t and substitute back into the expression

4t +4t -5t

4t+4t = 8t and substitute back into the expression

8t - 5t

3t

7 0
3 years ago
Three baseball players are playing catch. Philip is directly south of Barbara and directly west of Savannah. Philip and Savannah
Kitty [74]
Philip and Barbara are 8 meters apart because 5+3=8 so it will make 8 meters
4 0
2 years ago
What is the exponential regression equation that fits these data? y x 1 4 2 8 3 27 4 85 5 250 6 600
Volgvan

Answer:

its is C because the other ones are obvious wrong. So it has to be C plus i did this test.

Step-by-step explanation:

5 0
3 years ago
2x+y+4z=16<br> 5x-2y+2z=-1<br> X+2y-3z=-9
LekaFEV [45]

Answer:

24

Step-by-step explanation:

6 0
3 years ago
9/20
Stella [2.4K]

<u>Question:</u>

Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0

<u>Answer:</u>

The number of real solutions for the equation x^{2}+5 x+7=0 is zero

<u>Solution:</u>

For a Quadratic Equation of form : a x^{2}+b x+c=0  ---- eqn 1

The solution is x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}  

Now , the given Quadratic Equation is x^{2}+5 x+7=0  ---- eqn 2

On comparing Equation (1) and Equation(2), we get

a = 1 , b = 5 and c = 7

In x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a} , b^2 - 4ac is called the discriminant of the quadratic equation

Its value determines the nature of roots

Now, here are the rules with discriminants:

1) D > 0; there are 2 real solutions in the equation

2) D = 0; there is 1 real solution in the equation

3) D < 0; there are no real solutions in the equation

Now let solve for given equation

D= b^2 - 4ac\\\\D = 5^2 - 4(1)(7)\\\\D = 25 - 28 \\\\D = -3

Since -3 is less than 0, this means that there are 0 real solutions in this equation.

4 0
4 years ago
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