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2 years ago

Yo could anyone help me with this question chance to get brainliest and please and thank you

Mathematics

1 answer:

Bogdan [553]2 years ago

4 0

Answer: B: Gabriel opened the account with $15 and is depositing $35 per week into his bank account.

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(x+6) is a factor of f(x). Solve f(x)=0.<br>x3 - 52x – 96

Mars2501 [29]

<h3>I'll teach you how to solve f(x)=0x63 - 52x – 96</h3>

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f(x)=0x^3 - 52x – 96

Apply rule:

0 * a= 0

0-52x-96

Group like terms:

-52x+0-96

Add/subtract the numbers:

0-96= -96

-52x-96

Your Answer Is -52x-96

plz mark me as brianliest if this helped :)

6 0

3 years ago

tim earns $150/week plus $15.00 for each desk he assembles. Write an inequality to represent how many desks he needs assemble to

Gennadij [26K]

x = number of desks needed to make

equation: 150 +15.50x >= 400

solution:

150 +15.50x >=400

15.50x = 250

x = 250/15.50 = 16.129

he needs to assemble 17 desks

15.50*17 = 263.50 +150 = $413.50

3 0

3 years ago

Suppose a batch of metal shafts produced in a manufacturing company have a population standard deviation of 1.3 and a mean diame

lbvjy [14]

Answer:

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

$\mu = 208, \sigma = 1.3, n = 60, s = \frac{1.3}{\sqrt{60}} = 0.1678$

What is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Lesser than 208 - 0.1 = 207.9 or greater than 208 + 0.1 = 208.1. Since the normal distribution is symmetric, these probabilities are equal, so we find one of them and multiply by 2.

Lesser than 207.9.

pvalue of Z when X = 207.9. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{207.9 - 208}{0.1678}$