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Roman55 [17]
3 years ago
7

I need help! Math question

Mathematics
1 answer:
iren2701 [21]3 years ago
8 0
Again, a spreadsheet or suitable calculator makes this short work.

The sum is 184.

_____
The terms being summed are ...
  2·3² +3 = 2·9 +3 = 18 +3 = 21
  2·4² +3 = 35
  2·5² +3 = 53
  2·6² +3 = 75
Their total is
  21 +35 +53 +75 = 184

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Roger made a table showing how he spent his time in one day. How many days
Kazeer [188]

Answer:

3 days will pass

Step-by-step explanation:

work 24×1/3=8

sleep 24×3/8=9

meals 24×1/8=3

computer 24×1/6=4

reach up to 24 with sleep

9+9+9=27

which took a little over 3 days

5 0
2 years ago
Y = -2x + 2 y = 5x + 9​
WITCHER [35]
X=-1 y=4 hope it helps
8 0
3 years ago
Linear Equations, Functions, and Inequalities<br> Using Equivalent Systems of Equations<br> Warm-Up
navik [9.2K]
Okay I got it. Explan- My head
6 0
3 years ago
The nurse needs to mix 2% solution with 10% solution to get 10 ml of the prescribed 6% solution. What amount of each solution do
xenn [34]

<em>Volumes of 2% Solution = </em><em>5 ml</em>

<em>Volumes of 10% Solution = </em><em>5 ml</em>

\texttt{ }

<h3>Further explanation</h3>

Simultaneous Linear Equations could be solved by using several methods such as :

  • <em>Elimination Method</em>
  • <em>Substitution Method</em>
  • <em>Graph Method</em>

If we have two linear equations with 2 variables x and y , then we need to find the value of x and y that satisfying the two equations simultaneously.

Let us tackle the problem!

\texttt{ }

<em>Let:</em>

<em>Volumes of 2% Solution = x</em>

<em>Volumes of 10% Solution = y</em>

\texttt{ }

<em>Total Volume = 10 ml</em>

\boxed{x + y = 10} → <em>Equation 1</em>

\texttt{ }

<em>The nurse needs to mix 2% solution with 10% solution to get 10 ml of the prescribed 6% solution</em>.

2 \% x + 10 \% y = 6 \% (10)

2x + 10y = 6(10)

\boxed{x + 5y = 30} → <em>Equation 2</em>

\texttt{ }

<em>Equation 1 - Equation 2:</em>

( x + y ) - ( x + 5y ) = 10 - 30

-4y = -20

y = -20 \div -4

y = 5 \texttt{ ml}

\texttt{ }

x + y = 10

x + 5 = 10

x = 5 \texttt{ ml}

\texttt{ }

<h2>Conclusion:</h2>

<em>Volumes of 2% Solution = </em><em>5 ml</em>

<em>Volumes of 10% Solution = </em><em>5 ml</em>

\texttt{ }

<h3>Learn more</h3>
  • Perimeter of Rectangle : brainly.com/question/12826246
  • Elimination Method : brainly.com/question/11233927
  • Sum of The Ages : brainly.com/question/11240586

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Simultaneous Linear Equations

Keywords: Simultaneous , Elimination , Substitution , Method , Linear , Equations

6 0
3 years ago
The average daily jail population in the United States is 706,242. If the distribution is normal and the standard deviation is 5
Karolina [17]

a. The probability that on a randomly selected day, the jail population

is greater than 750,000 is 20.1%

b. The probability that on a randomly selected day, the jail population is

between 600,000 and 700,000 is 43.2%

Step-by-step explanation:

The given is:

1. The average daily jail population in the United States is 706,242

2. The distribution is normal and the standard deviation is 52,145

3. We need to find the probability that on a randomly selected day,

    the jail population is greater than 750,000

4. We need to find the probability that on a randomly selected day,

    the jail population is between 600,000 and 700,000

a.

At first find z-score

∵ z = (x - μ)/σ, where x is the score, μ is the mean and σ is the standard

   deviation

∵  x = 750,000 , μ = 706,242 and σ = 52,145

∴ z = \frac{750,000-706,242}{52,145} ≅ 0.84

Use the normal distribution table of z to find the area to the right of

the z-value

∵ The corresponding area to z-score of 0.84 is 0.79955

- But we are interested in x > 750,000, we need the area to the

  right of z-score

∴ P(x > 750,000) = 1 - 0.79955 = 0.2005

∴ P(x > 750,000) = 0.2005 × 100% = 20.1%

The probability that on a randomly selected day, the jail population is

greater than 750,000 is 20.1%

b.

We will find z-score for 600,000 < x < 700,000

∵ z = \frac{600,000-706,242}{52,145} ≅ -2.04

∵ z = \frac{700,000-706,242}{52,145} ≅ -0.12

Use the normal distribution table of z to find the area between

the two z-values

∵ The corresponding area to z-score of -2.04 is 0.02068

∵ The corresponding area to z-score of -0.12 is 0.45224

- To find P(600,000 < x < 700,000) subtract the two values above

∴ P(600,000 < x < 700,000) = 0.45224 - 0.02068 = 0.4316

∴ P(600,000 < x < 700,000) = 0.4316 × 100% = 43.2%

The probability that on a randomly selected day, the jail population is

between 600,000 and 700,000 is 43.2%

Learn more:

You can learn more about z-score in brainly.com/question/7207785

#LearnwithBrainly

5 0
3 years ago
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