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Brrunno [24]
3 years ago
15

Name the postulate or theorem you can use to prove the triangles congruent

Mathematics
1 answer:
Lesechka [4]3 years ago
6 0

Answer:

ASA

Step-by-step explanation:

if you understood the other, similar questions now, this one is really, really easy.

we got the confirmation for 2 angles and the side between these angles.

so, angle side angle or ASA

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Find the Solution of 2cos^2x + 3sin x =0
Evgen [1.6K]
2cos^2 x + 3sin x = 0
2(1 - sin^2 x) + 3sin x = 0
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5 0
3 years ago
Your school is sponsoring a pancake dinner to raise money for a field trip. You estimate that 200 adults will attend. You are tr
AfilCa [17]

Answer:

Some of the possible combinations are;

1) $19 per adult, $0 per child

2) $10 peer adult, $9 per child

3) $14 peer adult, $5 per child

Step-by-step explanation:

The given information are;

The estimated number of adults to attend the fund raising dinner = 200 adults

The amount the fund raiser is trying to realize = 3800

Therefore, some of the possible combinations are;

1) 3800/200 = 19 per adult to give;

$19 per adult, $0 per child

2) Given that each adult is charged $10, we have;

Total amount from adults = $10 × 200 = $2000

The total amount to be raised from the children = The amount the fund raiser is to realize - (Total amount from adults)

∴ The total amount to be raised from the children = 3800 - 2000 = 1800

The total amount to be raised from the children = $1,800

If there are 200 children we have;

The amount charged per child = (The total amount to be raised from the children)/(The total number of children)

The amount charged per child = $1,800/200 = $9 per child

Therefore, we have;

$10 peer adult, $9 per child

3) If each of the 200 children are charged $5 each, we have;

The total amount to be raised from the children = $5 × 200 = $1,000

∴ The amount to be raised from adults = $3800 - $1000 = $2800

The amount to each adult is to be charged = $2800/200 = $14

Therefore, we have;

$14 peer adult, $5 per child.

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3 years ago
What is the volume of a sphere with a radius of 5.9 in, rounded to the nearest tenth of a cubic inch?
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\textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=5.9 \end{cases}\implies V=\cfrac{4\pi (5.9)^3}{3}\implies V\approx 860.3~in^3

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