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Delvig [45]
3 years ago
6

Pleas help this is due today!!

Mathematics
1 answer:
harkovskaia [24]3 years ago
8 0
I can tell this activity is about graphing, but the writing is barely legible, can you re-upload the pictures or write it out?
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Please answer correctly !!!!!!!!!! Will mark brianliest !!!!!!!!!
evablogger [386]

Answer:5 milllion

And the minimum is 25

Step-by-step explanation:

4 0
3 years ago
(9-a+5a)/c (a=6,c=9)
SIZIF [17.4K]
\frac{9-a+5a}{c} = \frac{9-(6)+5(6)}{(9)}= \frac{3+30}{9} = \frac{33}{9} = \frac{11}{3}
7 0
3 years ago
What is the slope of the line represented by the equation y=- } - 5x?
Zepler [3.9K]

Answer:

The slope of the line represented by y = -5x is "-5".

Step-by-step explanation:

y=mx+b

M=slope

b=Y-intecerpt

5 0
3 years ago
Read 2 more answers
(1+cos2x)/(1-cos2x) = cot^2x
sesenic [268]

We will turn the left side into the right side.

\dfrac{1 + \cos 2x}{1 - \cos2x} = \cot^2 x

Use the identity:

\cos 2x = \cos^2 x - \sin^2 x

\dfrac{1 + \cos^2 x - \sin^2 x}{1 - ( \cos^2 x - \sin^2 x)} = \cot^2 x

\dfrac{1 - \sin^2 x + \cos^2 x }{1 - \cos^2 x + \sin^2 x} = \cot^2 x

Now use the identity

\sin^2 x + \cos^2 x = 1 solved for sin^2 x and for cos^2 x.

\dfrac{\cos^2 x + \cos^2 x }{\sin^2 x + \sin^2 x} = \cot^2 x

\dfrac{2\cos^2 x}{2\sin^2 x} = \cot^2 x

\dfrac{\cos^2 x}{\sin^2 x} = \cot^2 x

\cot^2 x = \cot^2 x


8 0
3 years ago
If QRST is a rectangle with QT = 30 and RS = 4x + 10, find x.
ArbitrLikvidat [17]
The opposite side pairs in a rectangle are congruent, so basically QT would be congruent to RS when you draw the rectangle and label the points.
4x+10=30
4x=20
x=5
4 0
3 years ago
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