Answer:
the distance is 7 units
Step-by-step explanation:
Since the we calculate the distance between (-2,4) and (5,4) and those points have the same y=4 coordinate then they are both part of a horizontal line.
The distance is found by looking at the x-axis.
From -2 to 5 so is form -2 until 0 is (2 )+ (5 )more = 7
Answer:
Step-by-step explanation:
First, look at y = log x. The domain is (0, infinity). The graph never touches the vertical axis, but is always to the right of it. A real zero occurs at x = 1, as log 1 = 0 => (1, 0). This point is also the x-intercept of y = log x.
Then look at y = log to the base 4 of x. The domain is (0, infinity). The graph never touches the vertical axis, but is always to the right of it. Again, a real zero occurs at x = 1, as log to the base 4 of 1 = 0 => (1, 0).
Finally, look at y=log to the base 4 of (x-2). The graph is the same as that of y = log to the base 4 of x, EXCEPT that the whole graph is translated 2 units to the right. Thus, the graph crosses the x-axis at (3, 0), which is also the x-intercept.
Step-by-step explanation:
Answer is attached....of both the parts.
Hope it helps:)
Hey there!
This can be written as
![n^{2}-(7)^{2}](https://tex.z-dn.net/?f=%20n%5E%7B2%7D-%287%29%5E%7B2%7D)
This is in form of
![\fbox{a^{2}-b^{2}}](https://tex.z-dn.net/?f=%5Cfbox%7Ba%5E%7B2%7D-b%5E%7B2%7D%7D)
, it can be expanded as
=> (n-7)(n+7)=0
=> n -7 = 0 or n + 7 = 0
=> n = 7 or n = -7
So option 7 , -7 are correct.
Hope this is clear :)
Have a good day:)