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3 years ago

15

MS. Candos has 90 invitations to hand out. she will hand out 42 of them the rest will be handed out by 6 students how many got h

anded out an equal number if invitations

1 answer:

kicyunya [14]3 years ago

6 0

90-42=48
48/6 = 8
The 6 student each handed out 8 invitation

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Priyanti ate 150 raisins in five days. If she ate 7 more raisins each day than she did the previous day, how many raisins did sh

marta [7]

Answer:

this means she ate an average of 30 raisins each day

so she ate 30 on the third day

so the amount she ate each day is like this

1. 16

2. 23

3. 30

4. 37

5. 44

16 + 23 +30 +37 +44=150

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2 years ago

Read 2 more answers

Calculate the surface area of the figure below.

valentinak56 [21]

Answer:

a. 1,275.49 m²

Step-by-step explanation:

SA = 2πr² + 2πrh

SA = 2π(7)² + 2π(7)(22)

SA = 98π + 308π

SA = 406π

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3 years ago

Work out the equation of the line which has a gradient of -2 and passes through the point (1,7)

Ilya [14]

point slope form of a line

y-y1 = m(x-x1)

y-7 = -2 (x-1)

if you want it in slope intercept form

y-7 = -2x +2

add 7 to each side

y = -2x +9

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2 years ago

In triangle ABC, AB = 5 inches and BC = 3 inches. Which of the choices represents all possible values for AC, inches?

shusha [124]

Answer:

-2 < AC < 8

Step-by-step explanation:

The last side has to be less than the sum of the other 2 sides, or less than 8. The only answer choice with this is the 3rd one.

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2 years ago

31. For the following exercises, given each set of information, find a linear equation satisfying the conditions, if possible.

Whitepunk [10]

Answer:

The required linear equation satisfying the given conditions f(-1)=4 and f(5)=1 is $y=\frac{-1}{2} x+\frac{7}{2}$

Step-by-step explanation:

It is given that f(-1)=4 and f(5)=1.

It is required to find out a linear equation satisfying the conditions f(-1)=4

and f(5)=1. linear equation of the line in the form

$\left(y-y_{2}\right)=m\left(x-x_{2}\right)$

Step 1 of 4

Observe, f(-1)=4 gives the point (-1,4)

And f(5)=1 gives the point (5,1).

This means that the function f(x) satisfies the points (-1,4) and (5,1).

Step 2 of 4

Now find out the slope of a line passing through the points (-1,4) and (5,1),

$\begin{aligned}&m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\&m=\frac{1-4}{5-(-1)} \\&m=\frac{-3}{5+1} \\&m=\frac{-3}{6} \\&m=\frac{-1}{2}\end{aligned}$

Step 3 of 4

Now use the slope $m=\frac{-1}{2}$ and use one of the two given points and write the equation in point-slope form:

$(y-1)=\frac{-1}{2}(x-5)$

Distribute $\frac{-1}{2}$ ,

$y-1=\frac{-1}{2} x+\frac{5}{2}$

Step 4 of 4

This linear function can be written in the slope-intercept form by adding 1 on both sides,

$\begin{aligned}&y-1+1=\frac{-1}{2} x+\frac{5}{2}+1 \\&y=\frac{-1}{2} x+\frac{5}{2}+\frac{2}{2} \\&y=\frac{-1}{2} x+\frac{7}{2}\end{aligned}$

So, this is the required linear equation.

8 0

2 years ago