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amid [387]
2 years ago
7

Janet can make 1/3 of a necklace in 15 minutes. At this rate, how many can she make in an hour? *

Mathematics
2 answers:
miskamm [114]2 years ago
8 0

Answer:

Janet can make 1  1/3 in an hour.

Step-by-step explanation:

1/3 x 3 = 1

15 x 3 = 45

lubasha [3.4K]2 years ago
5 0

Answer: easy the answer is 1 1/3

Step-by-step explanation:

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Alex has 84 quarters and nickels worth a total of $17.80.
Hunter-Best [27]

The equation which can be used to find the number of quarters and nickels is; n + q = 84, 0.05n + 0.25q = 17.80.

<h3>Quarters and nickels</h3>

  • Total coins = 84
  • Total value = $17.80

let

  • Number of quarters = q
  • Number of nickels = n

n + q = 84

0.05n + 0.25q = 17.80

From equation (1)

n = 84 - q

Substitute into (2)

0.05n + 0.25q = 17.80

0.05(84 - q) + 0.25q = 17.80

4.2 - 0.05q + 0.25q = 17.80

- 0.05q + 0.25q = 17.80 - 4.2

0.20q = 13.60

q = 13.60 / 0.20

q = 68

Substitute q = 68 into

n + q = 84

n + 68 = 84

n = 84 - 68

n = 16

Therefore, the number of quarters and nickels are 68 and 16 respectively.

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6 0
2 years ago
Choose the inequality that represents the following graph.
MissTica
Can you format it properly it’s confusing to read in this for
5 0
3 years ago
Consider a deck with 2626 black and 2626 red cards. You draw one card at a time and you can choose either guess on whether it is
gregori [183]

The maximum earning is v(r,b)

Let v(r,b) be the expected value of the game for the player, assuming optimal play, if the remaining deck has r red cards and b black cards.

Then v(r,b) satisfies the recursion

and

The stopping rule is simple: Stop when v(r,b)=0.

To explain the recursion . . .

If r,b>0, and the player elects to play a card, then:

  • The revealed card is red with probability \frac{r}{r+b}, and in that case, the player gets a score of +1, and the new value is V(r-1,b)
  • The revealed card is black with probability \frac{b}{r+b}, and in that case, the player gets a score of −1, and the new value is V(r,b-1)

Thus, if r,b>0, electing to play a card yields the value f(r,b).

But the player always has the option to quit, hence, if r,b>0, we get v(r,b)=max(0,f(r,b)).

Implementing the recursion in Maple, the value of the game is

v(26,26)=41984711742427/15997372030584

v(26,26)  ≈2.624475549

and the optimal stopping strategy is as follows . . .

  • If 24≤b≤26, play while r≥b−5.
  • If 17≤b≤23, play while r≥b−4.
  • If 11≤b≤16, play while r≥b−3.
  • If 6≤b≤10, play while r≥b−2.
  • If 3≤b≤5, play while r≥b−1.
  • If 1≤b≤2, play while r≥b.
  • If b=0, play while r>0.  

So, The maximum earning is v(r,b)

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4 0
2 years ago
Evaluate t2-s•8/s when s=3 and t=4
Eduardwww [97]

Answer:

b

Step-by-step explanation:

4² -3×8÷2/3+5

then multiply -3×8= -24

then 4²-24÷2

then divide -24÷2 = -12

then subtract 16-12=4

then that leaves 4/8= 1/2

4 0
3 years ago
Evaluate the expression for the given value of the variable(s).
slavikrds [6]
<span>[4b-4]+3-b^2]+2b^3 ;b=2

= </span><span>[4(2)-4]+3-2^2]+2(2^3)
=</span> [8-4] + 3 - 4]+2(8)
= [4 + 3 - 4]+2(8)
=3 + 16
=19
answer is <span>A. 19</span>
7 0
3 years ago
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