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Dominik [7]
3 years ago
14

May I eat some help please

Mathematics
2 answers:
Alekssandra [29.7K]3 years ago
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xxTIMURxx [149]3 years ago
3 0
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Hshehebeirjiejeueb why
Aleksandr [31]

Answer:

chinese?

Step-by-step explanation:

7 0
3 years ago
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A slide 4.4 m long makes an angle of 33 with the ground. How high is the top of the slide above the ground
svp [43]
Using the information given we will only need the Cosine and Sine equations.  i made a diagram (cant take a picture, in my study hall) labeled the sides of the triangle A, B, and C.  with C as the hypotenuse, A as the Opposite, and B as the adjacent (will not be needed as A is the height). i will be rounding the th nearest thousandth. 
Using Sine (SIN=Opposite/Hypotenuse), we can find A.

SIN(33)=A/4.4

SIN(33)≈.545

.545≈A/4.4

now multiply each side by 4.4 to get rid of the division

(.545*4.4)≈((A/4.4)4.4)

2.396≈A
 

so the answer would be that the slide is about 2.396 M high
5 0
3 years ago
2 ( −14 + r ) − ( −3r − 5 )
svet-max [94.6K]
-28+2r+3r+5 
simplified it is -23+5r
4 0
3 years ago
Read 2 more answers
We want to find the zeros of this polynomial:
fredd [130]

Answer:

x = -3 and x = -3/2

Step-by-step explanation:

After writing down the polynomial, split it; put a line between 3x^2 and -18x. Look and 2x^3 + 3x^2 and -18x - 27 separately and factor them both:

p(x) = 2x^3 + 3x^2 <u>- 18x -27</u>

p(x) = x^2(2x+3) <u>-9(2x+3)</u>

Now notice how x^2 and -9 have the same factor (2x+3). That means x^2 and -9 can go together:

p(x) = (x^2 - 9)(2x+3)

Factor it once more because there's a difference of squares:

p(x) = (x+3)(x-3)(2x+3)

Now just plug in whatever makes the each bracket equal 0:

x = -3, x = 3, and x = -3/2

Those are your zeros.

8 0
3 years ago
Brian is solving the equation x^2 -3/4 x =15. what value must be added to both sides of the equation to make the left side a per
vekshin1
To complete the square we get the coefficient of x, divide it by 2 then square it.
-3/4 divided by 2 =
-3/8 and then squared it equals
9 / 64
answer is a


3 0
3 years ago
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