10 to 11 = 1 hr
11 to 12 = 1 hr
12 to 1 = 1 hr
total = 3 hours
Answer:
a = 2(vt -d)/t^2
Step-by-step explanation:
Add the term containing "a":
d + a(t^2/2) = vt
Subtract d:
a(t^2/2) = vt -d
Multiply by the inverse of the coefficient of "a":
a = 2(vt -d)/t^2
To find f(g(x)), we'll treat g(x) as if it were the x in f(x).
g(x) = x + 3
f(g(x) = (x+3)^2 - 1
the answer is negative ten
-10