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Grace [21]
3 years ago
15

4.9 Code Practice: Question 3

Computers and Technology
2 answers:
Ksivusya [100]3 years ago
7 0

Answer:

sum = 0

for r in range (99, 0, -1):

   sum += r

   print(sum)

Explanation:

Zanzabum3 years ago
6 0

total = 0

for x in range(99, 0, -1):

   total += x

   print(total)

I hope this helps!

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Write a Java program that generates a new string by concatenating the reversed substrings of even indexes and odd indexes separa
salantis [7]

Answer:

/ReversedEvenOddString.java

import java.util.Scanner;

public class ReversedEvenOddString {

   public static void main(String[] args) {

       Scanner sc = new Scanner(System.in);

       String s = sc.nextLine();

       String evens = "";

       String odds = "";

       for(int i = s.length()-1;i>=0;i--){

           if(i%2==1){

               odds += s.charAt(i);

           }

           else{

               evens += s.charAt(i);

           }

       }

       String res;

       if(s.length()%2==1){

           res = evens+odds;

       }

       else{

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}

8 0
4 years ago
What type of network does not have centralized control, such as one in a small office or home office?
ella [17]
The answer is P.2.P

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7 0
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How are the functions different and how do i determine the answer
worty [1.4K]

Answer:

this isn't a fair question...

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3 0
3 years ago
In a study of 1228 randomly selected medical malpractice​ lawsuits, it was found that 856 of them were dropped or dismissed. Use
ale4655 [162]

Answer:

<u>Hypothesis</u><u> </u>

H o : No difference between proportions

H 1 : There is a significant difference between proportions

n = 1228

b = 1228 - 856

b = 375

Since n ≥ 25

b = {( a + 0.5 ) - n/2 }\  ( √n )/2

   = {( 372 + 0.5 ) - 1228/2 }\ ( √1228 )/2

   = - 13.789

  • from table : A-2
  • p-value is 0.000
  • given significance level is α = 0.01
  • p-value is less than significance level hence there is enough evidence to reject null hypothesis
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4 years ago
Name a network device which would have to be
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Answer:

network interface card (NIC).

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