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kumpel [21]
3 years ago
12

Two shapes with equal perimeter are pictured below.

Mathematics
1 answer:
Arlecino [84]3 years ago
3 0

Answer:

5

Step-by-step explanation:

did test give 5 star and thanks.

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Solve the following system of equations:<br><br> x + 3y = −4<br> x + 5y = −6<br><br> pls and thx
Agata [3.3K]

Answer:

x = -1  y = -1

Step-by-step explanation:

x + 3y = −4

x + 5y = −6

Multiply the first equation by -1

-x - 3y = 4

The add to the second equation to eliminate x

-x - 3y = 4

x + 5y = −6

--------------------

 2y = -2

Divide by 2

2y/2 = -2/2

y = -1

Now solve for x

x+3y = -4

x +3(-1) = -4

x -3 = -4

Add 3 to each side

x-3+3 = -4+3

x = -1

4 0
3 years ago
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2.Draw a diagram to represent each of these situations. Then write an addition expression that represents the final temperature.
Crazy boy [7]
Wait can you draw diagrams on here?
3 0
3 years ago
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steposvetlana [31]
<span>m, because triangle ABC is similar to triangle EDC  (by 3 congruent angles).</span>
6 0
3 years ago
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Write an equation of the line that passes through each points (5,6) (3.4)
ioda

Answer:

y = x + 1.

Step-by-step explanation:

Start by finding the slope of this line.

If a slanting line goes through (x_{0},\, y_{0}) and (x_{1},\, y_{1}), where x_{0} \ne x_{1}, the slope of this line would be:

\begin{aligned}m &= \frac{y_{1} - y_{0}}{x_{1} - x_{0}}\end{aligned}.

The line in this question goes through (5,\, 6) and (3,\, 4). Hence, the slope of this line would be:

\begin{aligned}m &= \frac{y_{1} - y_{0}}{x_{1} - x_{0}} \\ &= \frac{6 - 4}{5 - 3} \\ &= 1\end{aligned}.

If a slanting line with a slope of m and goes through the point (x_{0},\, y_{0}), the equation of this line in the point-slope form would be:

y - y_{0} = m,\, (x - x_{0}).

For the line in this question, the slope is m = 1. Take (5,\, 6) as the chosen point on this line. The point-slope form equation of this line would be:

y - 6 = (x - 5).

Rewrite to obtain the equation of this line in the slope-intercept form:

y = x + 1.

7 0
3 years ago
Assume the competing hypotheses take the following form: H0: µ1 – µ2 = 0, HA: µ1 – µ2 ≠ 0, where µ1 is the population mean for p
DedPeter [7]

Answer:

t=\frac{\bar x_1- \bar x_2}{\sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2} } }

Step-by-step explanation:

H0: µ1 – µ2 = 0

HA: µ1 – µ2 ≠ 0

We have given,

The population variances are not known and cannot be assumed equal.

The test statistic for the test is

t=\frac{\bar x_1- \bar x_2}{\sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2} } }

Where,

\bar x_1 = sample meaan of population 1

\bar x_2 = sample mean of population 2

n_1 = sample size of population 1

n_2 = sample size of population 2

Therefore, this is the test

t=\frac{\bar x_1- \bar x_2}{\sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2} } }

7 0
3 years ago
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