Anything to a negative power becomes the inverse with the coefficient to a positive power.
For example, 3^-1 becomes 1/3^1 or just 1/3.
3^-2 would be 1/3^2 or 1/9.
The value of QR for the given line will be 15 units.
<h3>What is a line segment?</h3>
A line section that can connect two places is referred to as a segment.
The line is here! It extends endlessly in both directions and has no beginning or conclusion.
In other terms, a line segment is merely a section of a larger, straight line that extends indefinitely in both directions.
Given,
PQ = RS
PR = 18
PS = 21
Now,
RS = PS - PR
RS = 21 - 18 = 3
So,
PQ = 3
Now,
QR = PR - PQ
QR = 18 - 3
QR = 15
Hence the value of QR will be 15 units.
For more about line segment
brainly.com/question/25727583
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Using relations in a right triangle, it is found that the length of AC is of 6.43 inches.
<h3>What are the relations in a right triangle?</h3>
The relations in a right triangle are given as follows:
- The sine of an angle is given by the length of the opposite side to the angle divided by the length of the hypotenuse.
- The cosine of an angle is given by the length of the adjacent side to the angle divided by the length of the hypotenuse.
- The tangent of an angle is given by the length of the opposite side to the angle divided by the length of the adjacent side to the angle.
In this problem, the length of side AC is b, which is opposite to the angle of 40º, while the hypotenuse is of 10 in, hence:


Using a calculator:

More can be learned about relations in a right triangle at brainly.com/question/26396675
Use this formula:
K = K_0 * (1+r)^n
Insert and solve for n:
12600 = 6000 * (1+0.065)^n
n = 11.78
So about 12 quarters.
Hope that helped.
Answer:
(b)
or 
Step-by-step explanation:
Given

See attachment for complete question
Required
Determine the volume of the cone
The volume of a square pyramid is:

Where
a = base dimension
From the attachment, the base dimension of the square pyramid is 2r.
So:

The volume becomes;

To calculate the volume of the cone, we simply multiply the given ratio and the volume of the prism.
So, we have:

![V_2 = \frac{\pi}{4} [ \frac{(2r)^2h}{3}]](https://tex.z-dn.net/?f=V_2%20%3D%20%5Cfrac%7B%5Cpi%7D%7B4%7D%20%5B%20%5Cfrac%7B%282r%29%5E2h%7D%7B3%7D%5D)

Open bracket;

Cancel out 4

The above can be written as:


So, we have:
![V_2 = \frac{\pi}{4} [ \frac{(2r)^2h}{3}]](https://tex.z-dn.net/?f=V_2%20%3D%20%5Cfrac%7B%5Cpi%7D%7B4%7D%20%5B%20%5Cfrac%7B%282r%29%5E2h%7D%7B3%7D%5D)
or
