2 years ago

Evaluate: xy+2x^2, if x=0.1 and y=9.8

Mathematics

2 answers:

shepuryov [24]2 years ago

6 0

Answer: 1

Step-by-step explanation:

$(0.1)(9.8)+2(0.1)^2\\0.98+0.02=1$

Elodia [21]2 years ago

4 0

Try Photomath! I always use the app for evaluating

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