The zeroes of the quadratic function f(x) = 6x² + 12x – 7 will be given below. Then the correct option is A.
<h3>What is a quadratic function ?</h3>
The quadratic function is given as ax² + bx + c = f(x).
For finding the zeroes of the polynomial we have to find the roots of the polynomial , The value of f(x) = 0
The given function is f(x) = 6x² + 12x – 7
Then the zeroes of the quadratic function will be
![roots = \dfrac {-b \pm \sqrt{b^2 -4ac}}{2a}\\\\](https://tex.z-dn.net/?f=roots%20%3D%20%5Cdfrac%20%7B-b%20%5Cpm%20%5Csqrt%7Bb%5E2%20-4ac%7D%7D%7B2a%7D%5C%5C%5C%5C)
Here a =6 , b = 12 ,c = -7
Therefore the zeroes are
![\rm roots = \dfrac {-12 \pm \sqrt{12^2 -4 * 6 * (-7)}}{2 *6}\\\\](https://tex.z-dn.net/?f=%5Crm%20roots%20%3D%20%5Cdfrac%20%7B-12%20%5Cpm%20%5Csqrt%7B12%5E2%20-4%20%2A%206%20%2A%20%28-7%29%7D%7D%7B2%20%2A6%7D%5C%5C%5C%5C)
![\rm root_1 = -1 + \sqrt{\dfrac {13}{6}}\\\\\rm root_2 = -1 - \sqrt{\dfrac {13}{6}}](https://tex.z-dn.net/?f=%5Crm%20root_1%20%3D%20-1%20%2B%20%5Csqrt%7B%5Cdfrac%20%7B13%7D%7B6%7D%7D%5C%5C%5C%5C%5Crm%20root_2%20%3D%20-1%20-%20%5Csqrt%7B%5Cdfrac%20%7B13%7D%7B6%7D%7D)
Therefore the correct option is A.
To know more about Quadratic Function
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▹ Answer
<em>1. x = -7</em>
2. y = 7
▹ Step-by-Step Explanation
x - y = -7
x - 0 =7
x = -7
x - y = -7
0 - y = -7
y = 7
Hope this helps!
- CloutAnswers ❁
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2 1/14 should be your answer
Answer:
6
Step-by-step explanation:
Pull terms out from of the radical,assuming positive real numbers .