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Tju [1.3M]
3 years ago
12

Find the value of x.

Mathematics
1 answer:
crimeas [40]3 years ago
3 0

Answer:

x = 50

Step-by-step explanation:

As you can see there is a straight line which mean the angle should be 180°.

180 = 76 + 2x + 4

180 = 80 + 2x

180 - 80 = 2x

100 = 2x

100/2 = x

50 = x

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Use the diagram below: H is the circumcenter of triangle BCD, BC = 18 and HD = 14. Find EH.
just olya [345]

Answer:

  • 10.72

Step-by-step explanation:

<h3>Given</h3>
  • H is the circumcenter of triangle BCD,
  • BC = 18
  • HD = 14
<h3>To find </h3>
  • Length of EH
<h3>Solution</h3>
  • Triangle BHD is isosceles, therefore BH = HD
  • Point E is midpoint of BC, therefore BE = 1/2BC

<u>Using Pythagorean, finding the value of EH:</u>

  • EH = √(BH² - BE²) = √(14² - (18/2)²) = √(196 - 81) = √115 = 10.72
7 0
3 years ago
Read 2 more answers
Which expressions have the same solution as -4(6)?
Alika [10]

Answer:

B, C, and [assumption] E.

Step-by-step explanation:

We are looking for an expression that is equal to -4(6). -4 * 6 = -24.

A. -4(-6)

-4 * -6 = 4 * 6 = 24

So, A does not have the same solution.

B. 4(-6)

4 * (-6) = -24

So, B has the same solution.

C. 6(-4)

6 * (-4) = -24

So, C has the same solution.

D. -8(2)

-8 * 2 = -16

So, C does not have the same solution.

E. 12(-2)

[I am not sure what number it is but I am <em>assuming</em> it is -2]

12 * (-2) = -24

So, <em>assumingly</em>, E has the same solution.

Hope this helps!

6 0
3 years ago
Read 2 more answers
The length of the rectangle is 4 times its width. If the
Oduvanchick [21]

Answer:

width is 8, length is 32

Step-by-step explanation:

* = multiply or times

Let the width be x, then the length would be 4x

Perimeter = 2*length+2*width

80 = 2*4x+2*x

80 = 8x+2x

80 = 10x

8 = x (width)

32 = 4x (length)

3 0
2 years ago
What is the value of |−8.6| ?
Brums [2.3K]
The value of |-8.6| is 8.6 because absolute value is always positive
8 0
3 years ago
How do find the domain and range of <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%7Bx-8%7D%7D" id="TexFormula1" tit
Kisachek [45]
\sqrt{x-8} is undefined if the argument x-8 is negative, so you first need to require that

x-8\ge0\implies x\ge8

We're not done yet, though, because \dfrac1{\sqrt{x-8}} still doesn't exist when x=8, so we remove this from the domain and we're left with x>8, or in interval notation, (8,\infty)

To find the range, consider the limits of the function as you approach either endpoint of the domain.

\displaystyle\lim_{x\to8^+}\frac1{\sqrt{x-8}}=+\infty
\displaystyle\lim_{x\to\infty}\frac1{\sqrt{x-8}}=0

Since \dfrac1{\sqrt{x-8}} is positive everywhere, the range is (0,\infty)
3 0
3 years ago
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