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Anna11 [10]
3 years ago
10

Which ordered pair is a solution to the equation y= 6x - 2?

Mathematics
1 answer:
Dmitry [639]3 years ago
4 0

Answer:

  • (5, 28)

Step-by-step explanation:

  • y= 6x - 2

Verifying pairs:

(1,0)

  • 0 = 6*1 - 2
  • 0 = 4 - incorrect

(5, 28)

  • 28 = 6*5 - 2
  • 28 = 30 -2
  • 28 = 28 - correct

(6, 20)

  • 20 = 6*6 - 2
  • 20 = 36 - 2
  • 20 = 34 - incorrect

(3, 19)

  • 19 = 6*3 - 2
  • 19 = 18 - 2
  • 19 = 16 - incorrect
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Solve for x: −2(x + 3) = −2(x + 1) − 4. (1 point)
NeTakaya

Answer:

Hey there!

Let's solve our equation below.

-2(x+3)= -2(x+1)-4

Let's distribute the parentheses.

-2x-6=-2x-2-4

We combine like terms.

-2x-6=-2x-6

We add 6 to both sides.

-2x=-2x

We divide both sides by -2

x=x

If, when solving an equation, you get one number or variable that equals itself, there are infinitely many solutions.

We can plug anything into this equation and it will always equal to same things, since x is just equal to whatever x value you want.

Therefore, there are infinitely many solutions.

I hope this helps!

8 0
3 years ago
Use the figure below to determine the length of sides b and c. options: b = 5√3, c = 10 b =10, c = 5√3 b = 5√2, c = 10√3 b = 5,
Reil [10]

Answer:

A

Step-by-step explanation:

8 0
3 years ago
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Anettt [7]

Answer:

The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.

Step-by-step explanation:

Let us take the point of projection of the ball as origin of the coordinate system, the upward direction as positive and down direction as negative.

Initial velocity u with which the ball is projected upwards = + 120 ft/s

Uniform acceleration a acting on the ball is to acceleration due to gravity = - 32 ft/s²

The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.

Using the formula:

v² - u² = 2 a h,

where

u = initial velocity of the ball = +120 ft/s

v = final velocity of the ball at the highest point = 0 ft/s

a = uniform acceleration acting on the ball = -32 ft/s²

h = height attained

Substituting the values we get;

0² - 120² = 2 × (- 32) h

=> h = 120²/2 × 32 = 225 feet

The height of the ball from the ground at its highest point = 225 feet + 12 feet = 237 feet.

7 0
3 years ago
What is the following product
frosja888 [35]
I would pick C sorry if it’s wrong
3 0
3 years ago
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What are the amplitude, period, and phase shift of the given function? f(t)=-2/3 cos (3t-3pi)
dybincka [34]

Answer:

amplitude; \frac{2}{3}

Phase shift; \pi units right

Period;\frac{2\pi}{3}

Step-by-step explanation:

The given function is

y=-\frac{2}{3}\cos(3t-3\pi)

This function is of the form;

y=A\sin (Bt+C)

The period is given by:

|A|=|-\frac{2}{3}|= \frac{2}{3}

The period is given by:

T=\frac{2\pi}{|B|}= \frac{2\pi}{|3|}=\frac{2\pi}{3}

The phase shift is given by;

\frac{C}{B}=\frac{-\3pi}{3}=- \pi or \pi units right.

4 0
3 years ago
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