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Anna11 [10]
2 years ago
10

Which ordered pair is a solution to the equation y= 6x - 2?

Mathematics
1 answer:
Dmitry [639]2 years ago
4 0

Answer:

  • (5, 28)

Step-by-step explanation:

  • y= 6x - 2

Verifying pairs:

(1,0)

  • 0 = 6*1 - 2
  • 0 = 4 - incorrect

(5, 28)

  • 28 = 6*5 - 2
  • 28 = 30 -2
  • 28 = 28 - correct

(6, 20)

  • 20 = 6*6 - 2
  • 20 = 36 - 2
  • 20 = 34 - incorrect

(3, 19)

  • 19 = 6*3 - 2
  • 19 = 18 - 2
  • 19 = 16 - incorrect
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A box contains 18 green marbles and 8 white marbles. If the first marble chosen was a white marble, what is the probability of c
murzikaleks [220]

Answer:

7/25

Step-by-step explanation:

Original contents of the box:

18 green marbles

8 white marbles

Contents of the box after drawing 1 white marble:

18 green marbles

7 white marbles

Total: 25 marbles

p(white) = (number of white marbles)/(total number of marbles)

p(white) = 7/25

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1 year ago
The probability that Barry Bonds hits a home run on any given at-bat is 0.16, and each at-bat is independent.
serious [3.7K]

Answer:

a) 0.0797 = 7.97% probability that the next home run will be on his fifth at-bat.

b) The expected number of at-bats until the next home run is 6.25.

Step-by-step explanation:

For each at bat, there are two possible outcomes. Either it is a home run, or it is not. The probability of an at bat resulting in a home run is independent of any other at-bat, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that Barry Bonds hits a home run on any given at-bat is 0.16

This means that p = 0.16

Part A: What is the probability that the next home run will be on his fifth at-bat?

0 on his next 4(P(X = 0) when n = 4)

Home run on his 5th at-bat, with 0.16 probability. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{4,0}.(0.16)^{0}.(0.84)^{4} = 0.49787136


0.49787136 *0.16 = 0.0797.

0.0797 = 7.97% probability that the next home run will be on his fifth at-bat.

Part B: What is the expected number of at-bats until the next home run?

The expected number of trials for n successes is given by:

E = \frac{n}{p}

In this question, n = 1, p = 0.16. So

E = \frac{1}{0.16} = 6.25

The expected number of at-bats until the next home run is 6.25.

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Suppose you start at the origin, move along the x-axis a distance of 4 units in the positive direction, and then move downward a
timurjin [86]

Answer:

(4,0,-7)

Step-by-step explanation:

The initial position was (0,0,0) since it was the origin

Now, we have a movement of positive x at a distance of 4 units, with a distance of z a total of 7 units(negative since downward)

The current position is thus;

(4,0,-7)

Thus correlates to (x,y,z) and our y has remained zero as there is no movement along the y-axis

8 0
3 years ago
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