Answer:
This is a question about accepted idiomatic usage and level of formality rather than a question of grammar. These forms are not technically “grammatically incorrect,” but neither are accepted idiomatic usage. If you want to be fluent in your usage, and you are willing to come off as formal and a bit peremptory and demanding, you would say, “I would appreciate it if you …” But unless you want to convey impatient formality, you would probably want to say instead, “I would be grateful if you …”
You would probably never in any circumstance say "I will appreciate if you.." or "I would appreciate if you.."
Step-by-step explanation:
And you would also probably never even say "I will appreciate it if you.." This is just not the way English speakers speak. One reason you wouldn’t say “I will appreciate it” (besides the fact that it would sound impatient) is that you need to use the subjunctive “would” when you are using “if,” instead of the predictive “will.” You are only predicting that if a hypothetical event occurs, appreciation will occur. For instance: You impatiently say, “I would appreciate it if you would pay your rent.” You are predicting (or sarcastically claiming to predict) that if the rent is paid, you will be appreciative.
Answer:
-30a^5b + 12a^4b^3 + 16a^3b^2 - 4a^2b^4 - 2 ab^3
Step-by-step explanation:
Answer:
-57.29
Step-by-step explanation:
Answer:
180 - 61 = 119
Step-by-step explanation:
So from A to D it is 180 degrees so just have to subtract 61 from 180 for an answer.
Answer:
0.0668 = 6.68% probability that the worker earns more than $8.00
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The average hourly wage of workers at a fast food restaurant is $7.25/hr with a standard deviation of $0.50.
This means that 
If a worker at this fast food restaurant is selected at random, what is the probability that the worker earns more than $8.00?
This is 1 subtracted by the pvalue of Z when X = 8. So
has a pvalue of 0.9332
1 - 0.9332 = 0.0668
0.0668 = 6.68% probability that the worker earns more than $8.00
