Answer:
0.04
Step-by-step explanation:
Given that a dart is to be thrown at a target. The probability the dart will hit the target (yes or no) on a single attempt is 0.20
Each throw is independent of the other throws.
Let x be the no of times the target is hit in the trial of 4 throws
Since each outcome is independent of the other X is binomial with n =4 and p = 0.20
Required probability
= the probability that it will take less than or equal to 4 throws to hit the target on both successful target hits
=P(X=2 when n =2) + P(x=2 when x =3) + P(x=2 when x =4)
= 
Answer:
The probability that a student is taking calculus given that he or she is taking statistics is = 0.26
Step-by-step explanation:
the probability that a student is taking calculus given that he or she is taking statistics.
Let C = Calculus
S = Statistics
We solve this above Question nursing the formula;
P ( C ∪ S) = P(C) + P ( S ) - P ( C ∩ S)
From the question,
P(C) = 0.10
P( S ) = 0.18
P ( C ∩ S) = 0.02
P ( C ∪ S) = ???
P ( C ∪ S) = 0.10 + 0.18 - 0.02
= 0.28 - 0.02
= 0.26
So what u do (-72828282)+(-7382828)=(-73838)+n=(-839288n)
So the man can wash lies Down
Answer:
10
Step-by-step explanation:
7 + 3 = 10
Not really that much to it lol
